Yes, 86.2 N sounds like a more accurate answer. Great job on your solution!

[Medgirl314]

Homework Statement

A 15 kg crate rests on the floor. The coefficient of friction between the crate and the floor is 0.28. How much horizontal force is needed to accelerate the crate at 3.0 m/s^2?

Homework Equations

F_net=ma

The Attempt at a Solution

m=15 kg
F-f=ma
F-MN=ma
F-Mmg=ma
F=ma+Mmg
F=15*3+.38*15*9.8
F=81.16 N.
For a final rounded answer of: F=81.2 N.

This answer seems correct to me, could someone please confirm?

Thanks!

 

[SteamKing]

Homework Statement

A 15 kg crate rests on the floor. The coefficient of friction between the crate and the floor is 0.28. How much horizontal force is needed to accelerate the crate at 3.0 m/s^2?

Homework Equations

F_net=ma

The Attempt at a Solution

m=15 kg
F-f=ma
F-MN=ma
F-Mmg=ma
F=ma+Mmg
F=15*3+.38*15*9.8 (0.28 is the μ in the prob. statement)
F=81.16 N.
For a final rounded answer of: F=81.2 N.

This answer seems correct to me, could someone please confirm?

Thanks!

I don't get your result, even with μ = 0.28. Try your calculator again.

 

[Medgirl314]

Oops, I thought I corrected that, sorry! Weird, I somehow mixed up the digits. Does 86.16, rounded to 86.2, sound better?

Thanks!