Yet another maxwell boltzman question

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The discussion revolves around calculating the average velocity \(\langle v_{x}\rangle\) for a one-dimensional Maxwell-Boltzmann distribution, where the expectation is that it equals zero. The provided distribution function is correct, but the integration limits are incorrectly set from 0 to ∞. To accurately compute \(\langle v_{x}\rangle\), the limits should be adjusted to range from -∞ to +∞, allowing for the inclusion of negative velocities. This adjustment is crucial for obtaining the correct average velocity in this context. Understanding the symmetry of the distribution is key to resolving the issue.
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I have posted a few questions on maxwell boltzman distribution, the problem this time is show:

\langle v_{x}\rangle=0

I believe the modified maxwell-boltz distrib. for one dimensional case is:

f(v_{x})=\sqrt{\frac{m}{2\pi kT}}e^{-\frac{mv_{x}^{2}}{2kt}}

My thinking was that simple plug it into the formula:

\langle v\rangle=\int_{0}^{\infty}vf(v)dv

and the integral should evaluate to 0 but the above clearly doesn't evaluate to 0.

Any advice on how to approach this problem is appreciated.
 
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The problem is not dealing with v but instead with vx, which can be negative. The integration limits should be from -∞ to +∞, not 0 to +∞.
 
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