Young's Double Slit Experiment lab

AI Thread Summary
The discussion centers on Young's double slit experiment, focusing on the relationship between the distance from the slits to the viewing screen and the spacing of the maxima. Participants explain that the increase in distance between successive maxima is due to fixed angles associated with the maxima and the application of trigonometric relationships. One contributor emphasizes the importance of understanding the mathematical basis behind the phenomenon, suggesting that the original question is valid and not trivial. The conversation also touches on the conditions under which the experiment is conducted, clarifying that it typically assumes a far-field scenario. Overall, the discussion aims to deepen the understanding of the wave nature of light as demonstrated in the experiment.
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In class we did a lab regarding the wave nature of light. We pretty much conducted Young's double slit experiment. For the lab we were supposed to establish the relationship between the distance from the slits to the viewing screen and the distance between successive maxima. Can anyone explain to me, physics wise, why as the distance between the viewing screen the distance between successive maxima increases proportionally as well. I can obviously figure it looking at the formula but need a explanation of what's going on for my lab. Thanks
 
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braeden said:
In class we did a lab regarding the wave nature of light. We pretty much conducted Young's double slit experiment. For the lab we were supposed to establish the relationship between the distance from the slits to the viewing screen and the distance between successive maxima. Can anyone explain to me, physics wise, why as the distance between the viewing screen the distance between successive maxima increases proportionally as well. I can obviously figure it looking at the formula but need a explanation of what's going on for my lab. Thanks

Er... this is straightforward trigonometry.

These maxima and minima are at particular angles. So if you look at the first maximum, it comes out of the slit at a fixed angle. So if you consider A as the distance to the screen and O is the distance to the first maximum, then if you keep the angle \theta fixed, can't you see that O will get larger as A increases?

right-triangle.JPG


Your a trig. function (I'll let you figure this out yourself which one is relevant) to relate the angle, distance A, and distance O, you should be able to get the exact relationship between all three.

In the future, please write down exactly the mathematical description that you know, and start from there.

Zz.
 
ZapperZ said:
Er... this is straightforward trigonometry.

These maxima and minima are at particular angles.

In the future, please write down exactly the mathematical description that you know, and start from there.

Zz.

It almost appears as if you are trying to make the original question sound as dumb. I wouldn't approve of that, because it is not obvious at all why the maxima and minima would come at particular angels. They do so only as an approximation when the distance between the slits is signifigantly smaller than the other distances in the situation. In order to prove this nicely, one of the most obvious ways (IMO) is to apply the approximation

<br /> \sqrt{1 + x} \approx 1 + \frac{x}{2}<br />

So that's the level of math that is required for this.
 
jostpuur said:
It almost appears as if you are trying to make the original question sound as dumb.

Er... no. I was pointing out the nature of the problem. Indicating that this is probably a math question might provide the OP a place to look. Furthermore, the OP indicated that he/she has the mathematical "formula" to look at. Knowing exactly what it is is the starting point since that is something the OP knows.

My philosophy in teaching has ALWAYS been to start where the understanding stops!

I wouldn't approve of that, because it is not obvious at all why the maxima and minima would come at particular angels. They do so only as an approximation when the distance between the slits is signifigantly smaller than the other distances in the situation. In order to prove this nicely, one of the most obvious ways (IMO) is to apply the approximation

<br /> \sqrt{1 + x} \approx 1 + \frac{x}{2}<br />

So that's the level of math that is required for this.

Do you really think that, at this level, this is not a far-field situation? Near-field 2-slit experiment is highly unusual. Based on the description given in the OP, I see this as being a standard, straightforward 2-slit experiment in an intro lab. Do you see otherwise?

Zz.
 
I believe the original problem was a far-field situation. I also believe that braeden has had difficulty understanding what it means.
 
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