Young's Slit Interference (Double Slit)

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To find the slit separation in a double slit arrangement producing interference fringes 11.5 mrad apart with a wavelength of 471.0 nm, the relevant equations are tan(theta) = y/D and a*sin(theta) = p * wavelength. The angle θ should be converted to radians for accurate calculations. The correct approach involves using the formula a*sin(11.5 mrad) = p*471 nm, while considering that the formula initially provided relates to minima, necessitating calculations for different orders of p. This ensures the determination of the slit separation is accurate for the observed fringe pattern.
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Find the slit separation of a double slit arrangement that will produce interference fringes 11.5 mrad apart on a distant screen with light of wavelength 471.0 nm.

tan(theta) = y/D
asin(theta) = p * wavelength

I know that I'm trying to solve for a, and that asin(theta) = 11.5, but I feel like I don't know enough information to solve the problem. Could someone point me in the right direction?
 
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The angle is θ = 11.5 mrad, the wavelength 471 nm so your expression should be more like
a*sin(11.5 mrad) = p*471 nm.
Be sure to get rid of the milli and the nano.

There is a little problem with that formula - it gives the angles for the minima whereas there is a maximum at θ = 0, so you'll have to do a couple of calculations perhaps for p = 1 and p = 2 to get a difference in angle between two minima.
 
Ah thanks. :)
 
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