Zinc Chloride: The Lewis Acid with Electrophilic Properties

  • Thread starter Thread starter hariharan venkatasu
  • Start date Start date
  • Tags Tags
    Acid Zinc
AI Thread Summary
Zinc chloride (ZnCl2) acts as a Lewis acid due to the zinc ion's ability to accept electron pairs, particularly into its 4s orbital after losing two electrons to form Zn2+. The discussion clarifies that the electron configuration of neutral zinc is [Ar]4s^2 3d^10, and in its ionic form, Zn2+, it becomes [Ar]3d^10, leaving the 4s orbital empty. Participants debate the filling order of orbitals based on the Aufbau principle, ultimately agreeing that the lowest energy orbitals available for electron acceptance in Zn2+ are the 4s orbitals, not the 4p or 4d. The conversation also touches on the nature of ZnCl2 as a partially ionic compound with covalent characteristics and the concept of electron deficiency in transition metal complexes. Understanding these principles is crucial for grasping zinc's behavior as a Lewis acid.
hariharan venkatasu
Messages
66
Reaction score
3
Zinc chloride is Electrophilic and so acts as a Lewis acid.This characteristic is due to it's ability to accept electrons to it's 4 d orbital.My question is why it receives electrons to it's 4 d orbital when 4 p remain empty( according to Aufbau diagram)?Are there any other d block element capable of accepting electrons to 4 d orbital leaving 4 p and 5 s orbitals ?
 
Chemistry news on Phys.org
hariharan venkatasu said:
This characteristic is due to it's ability to accept electrons to it's 4 d orbital.
Says who? This should be 3d.

edit: 4s, not 3d.
 
According to the configuration of zinc it is [Ar]3 d^ 10,4 s^2.As such there is no room for fresh electrons to enter 3 d .So the next option is 4 p. could you make this clear?
 
What is the electron configuration of zinc in ZnCl2? Hint: it’s not what you’ve written.
 
  • Like
Likes chemisttree
TeethWhitener said:
What is the electron configuration of zinc in ZnCl2? Hint: it’s not what you’ve written.
Beat me to it! 👍🏻
 
I am stuck here.Please help.
 
You have written the electronic configuration for neutral zinc. In the compound zinc chloride, is zinc neutral?
 
I agree that in Zn Cl 2 Zn is not neutral.It has donated electrons to chlorine forming Zn ion. I am appending a post from internet which mentions about 4 d orbital which I referred initially:-
The basic characteristics of a Lewis Acid is property of gaining electron

In ZnCl2 Electronic configuration of zinc is 3d ^10 so it has a tendency to accept electrons in its empty 4d orbitals so it act as Lewis acid

I hope this helps.
 
hariharan venkatasu said:
In ZnCl2 Electronic configuration of zinc is 3d ^10 so it has a tendency to accept electrons in its empty 4d orbitals so it act as Lewis acid
No, the 4d orbitals are way too high in energy to accept electrons. The zinc in ZnCl2 is Zn2+. If the electronic configuration of neutral zinc is [Ar]4s23d10 and in Zn2+ is [Ar]3d10, what orbital in Zn2+ do you think will accept electrons?
 
  • #10
Thank you for your reply.As a Lewis acid it will accept extra electrons and I feel electrons will enter 4 p orbitals.I don't whether I am right.Please enlighten me.
 
  • #11
Let’s try again: neutral zinc is [Ar]4s23d10 and Zn2+ is [Ar]3d10. If Zn2+ accepts an electron pair as a Lewis acid, which orbital will the electrons go into?
 
  • #12
As I wrote to you earlier the electrons should enter the empty 4 p orbital.Am I right?
 
Last edited:
  • #13
No you aren’t. From your Aufbau diagram, which electrons fill after 3d10?
 
  • #14
According to aufbau diagram the next orbital to be filled is 4 p and then 5 s
 
  • #15
Let’s try this the other way. If you start with neutral zinc [Ar]4s23d10 and you lose two electrons to get Zn2+ [Ar]3d10, which orbital became empty after the loss of the two electrons?
 
  • #16
hariharan venkatasu said:
According to aufbau diagram the next orbital to be filled is 4 p and then 5 s
Right. So you agree that 4p is higher energy than 4s? Both are empty in Zn+2.
 
  • #17
Still I am unable to know which orbital fresh electrons going to fill after 3 d in Zn+2
 
  • #18
hariharan venkatasu said:
Still I am unable to know which orbital fresh electrons going to fill after 3 d in Zn+2
Start by answering my question in post 15.
 
  • #19
According to your post 15 the 4 s orbital is empty after loss of two electrons
 
Last edited:
  • #20
hariharan venkatasu said:
According to your post 15 the 4 s orbital is empty after loss of two electrons
Ok so now read @chemisttree 's post 16. What is the lowest energy empty orbital in Zn2+?
 
  • #21
According to post 16 of chemisttree lowest empty orbital is 4 s in Zn+2
 
  • #22
hariharan venkatasu said:
According to post 16 of chemisttree lowest empty orbital is 4 s in Zn+2
Ok so according to Aufbau, which orbital in Zn2+ gets filled first?
 
  • #23
So according to aubau diagram 4 p is going to be filled first
 
  • #24
hariharan venkatasu said:
So according to aubau diagram 4 p is going to be filled first
What is the Aufbau principle, in your own words?
 
  • #25
TeethWhitener said:
What is the Aufbau principle, in your own words?
I think Hari has it now. We should let this info stew for a while until Hari has the epiphany I know is coming. Anything further is just trolling...
 
  • Like
Likes berkeman
  • #26
Aufbau principle, as I understand, says about addition of electrons to orbitals.Lower orbitals fill before higher orbitals do.Still I haven't got the answer to my problem.
 
  • #27
hariharan venkatasu said:
Lower orbitals fill before higher orbitals do

"Lower" is quite ambiguous, please refresh what the Aufbau principle really says.
 
  • Like
Likes jim mcnamara and hariharan venkatasu
  • #28
Aufbau principle says,in the ground state of an atom or ion,electrons fill atomic orbitals of the lowest energy levels first before occupying higher energy levels
 
  • #29
Even after so many posts I haven't received a final reply.Could you please help me?
 
  • #30
That is because we are trying to get you to see the answer.
1. put these, s , p, d, in order from lowest to highest energy level
2. Use the diagrams everyone has shown you to choose the lowest available energy level.
3. THE ANSWER IS NOT p.

If you do not come back with an answer, we are going to assume you are acting in bad faith. The thread will be locked. PF is not a homework answer machine, we are here to help you learn.
 
  • #31
In which case I feel 4 s is the lowest energy orbital
 
  • #32
Yes. So what what was the difficulty understanding that the electrons would occupy the lowest energy orbitals?
 
  • #33
Thank you for your reply.I was wondering how the electrons once left 4 s orbital leaving the zinc ion can rejoin the ion again?
 
  • #34
hariharan venkatasu said:
Thank you for your reply.I was wondering how the electrons once left 4 s orbital leaving the zinc ion can rejoin the ion again?
Your original question/observation was that ZnCl2 was a lewis acid because it accepted electrons into its 4d orbitals rather than the 4p orbitals. Are you now saying that you don’t understand how Zn+2 accepts electrons at all?
 
Last edited:
  • #35
Also, kinda iffy applying Aufbau to non-ground state atoms.

ZnCl2 is only partially an ionic compound. The Zn-Cl bonds have significant covalent character.

Perhaps your question should have been, “Why is ZnCl2 able to share additional electrons?” The s orbital is being used in the bond with chloride so the hand waving answer is that it can accept additional electron pairs (definition of Lewis Acid) to complete its octet. It has 4 electrons in its outer shell and would like an additional two pair. For electron pair donors, this would mean another two species capable of sharing two additional pairs are possible. Zinc is known to form tetrahedral complexes so that tracks with the analysis. In the case where zinc is tetrahedral it is due to the 4s and 4p orbitals hybridizing.

Zinc also forms trigonal bipyramid, square pyramid and octahedral complexes. In these complexes it is obvious that empty d orbitals are involved.

Your question was very general regarding zinc’s Lewis Acid character and the simplest answer to that question is that it is a cation that can accept an electron pair into its 4s.
 
  • Like
Likes HAYAO
  • #36
Thanks for the excellent answer
 
  • #37
In post number 35 it has been mentioned that"It has 4 electrons in its outer shell and it would like an additional two pair"How come this is so when it has only two electrons?Please clarify this.I am sorry for a late communication
 
  • #38
hariharan venkatasu said:
In post number 35 it has been mentioned that"It has 4 electrons in its outer shell and it would like an additional two pair"How come this is so when it has only two electrons?Please clarify this.I am sorry for a late communication
https://en.m.wikipedia.org/wiki/18-electron_rule
 
  • #39
Thank you for your information about the wikipedia article.However I don't find any clarification for my question.Could you please elaborate on this?
 
  • #40
hariharan venkatasu said:
Thank you for your information about the wikipedia article.However I don't find any clarification for my question.Could you please elaborate on this?
The 18-electron rule is a general rule of thumb like the Octet rule for predicting stability in transition metal complexes. In the case of zinc chloride, you get 10 electrons from the ##Zn^{2+}## and 2 electrons each from the chlorides, giving 14 electrons. Thus this compound is electron deficient, and can accept four more electrons (or 2 pairs) to satisfy the 18-electron rule. This is the broad reason why zinc chloride is a good Lewis acid.
 
  • Like
Likes HAYAO
  • #41
Thank you for the clarification.However it has kindled the following doubts.

--You have said that Zn2+ ion has 10 electrons and 2 electrons each from chlorides.These chlorides are the ones that left zinc chloride molecule
--Do they act as ligands and form coordinate bond?
--The configuration of zinc is 2,8,18,2.Does it mean zinc will have one more 18 electron?
--What will be the ultimate configuration of zinc chloride after accepting the extra electrons?
Could you please answer these also?
 
  • #42
I shall be immensely thankful if you could reply to my post 41.I am eager to hear from you
 
  • #43
Normally I used to see your reply quickly and promptly. There is an unusual delay in your replying.Could you kindly expedite your reply for post 41?Thanking you.
 
  • #44
Could you please reply to my post 41?I am eagerly waiting for the answers for my queries.Thanking you.
 
  • #45
hariharan venkatasu said:
Normally I used to see your reply quickly and promptly. There is an unusual delay in your replying.Could you kindly expedite your reply for post 41?Thanking you.
hariharan venkatasu said:
Could you please reply to my post 41?I am eagerly waiting for the answers for my queries.Thanking you.

Personally, I think they have done tremendous amount of job replying to you in a patient manner. I don't think reminding them like this would help you get any answer. Remember, they are doing a favor for you. They are not obliged in any way to answer your questions.

hariharan venkatasu said:
These chlorides are the ones that left zinc chloride molecule
--Do they act as ligands and form coordinate bond?
What do you mean "left" zinc chloride molecule? Chloride do act as a ligand.

--The configuration of zinc is 2,8,18,2.Does it mean zinc will have one more 18 electron?
--What will be the ultimate configuration of zinc chloride after accepting the extra electrons?
Could you please answer these also?
That kind of way of writing electron configuration are the ones you see in introductory high school textbooks (at least over here in Japan), but they are not very good in explaining the actual electronic configuration.
The thread has been about s, p, d, orbitals the entire time, so how about you write accordingly, eg 1s2, 2s2, 2p6, ...

If you can do that, then you should also be able to answer your other questions. Like they've been saying, use the Aufbau principle.
 
  • Like
Likes Greg Bernhardt
  • #46
I am extremely sorry if I have hurt you any way by sending reminders.It was my curiosity that prompted me to do so.I owe apologies.
Regarding zinc chloride when it ionizes the two chlorine ions leaving the molecule which is what I meant by "left". The electron configuration is 1 2 s^ 2 s^2 2 p^6 3 s^2 3 p^6 4 s^2 3 d^10
Once again my excuses and thanks for all the efforts you have put into answer my questions.
 
Back
Top