Zoroaster Planet Escape Speed Calculation for Meteor Collision

  • Thread starter Thread starter ~*Noor*~
  • Start date Start date
  • Tags Tags
    Escape Speed
Click For Summary
SUMMARY

The escape speed from the surface of Planet Zoroaster is 15.0 km/s, which is the minimum speed required for an object to break free from the planet's gravitational pull. A meteor traveling at 5.0 km/s towards Zoroaster will not simply add its speed to the escape speed. Instead, the meteor will accelerate towards the planet due to its gravitational field, resulting in a higher impact speed upon collision. The correct calculation involves considering gravitational acceleration, not merely summing the speeds.

PREREQUISITES
  • Understanding of gravitational acceleration and its effects on falling objects
  • Basic knowledge of escape velocity concepts
  • Familiarity with kinematic equations in physics
  • Ability to perform calculations involving relative velocity
NEXT STEPS
  • Study gravitational acceleration and its impact on falling objects
  • Learn about escape velocity and its applications in astrophysics
  • Explore kinematic equations for calculating motion under gravity
  • Investigate relative velocity concepts in collision scenarios
USEFUL FOR

Students of physics, astrophysicists, and anyone interested in understanding the dynamics of objects in gravitational fields and collision scenarios.

~*Noor*~
Messages
4
Reaction score
0
Q.) The escape speed from the surface of Planet Zoroaster is 15.0 km/s. The planet has no atmosphere. A meteor far away from the planet moves at speed 5.0 km/s on a collision course with Zoroaster. How fast is the meteor going when it hits the surface of the planet?

My answer:

15+5=20km/s since they both are going towards each other. But keep getting this answer wrong...i've tried 15km/s as well which is also wrong

What am i doing wrong here?
 
Physics news on Phys.org
The escape speed is not the translational speed of the planet. Its the the speed required to leave the planet. You'll have to take into account the acceleration of the meteor given by the planet's gravitational field. Since the meteor is far away from the planet at first, you can assume the initial acceleration to be around 0 m/s^2. But as the meteor approaches the planet, it will accelerate towards it.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
6
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
15
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 62 ·
3
Replies
62
Views
5K