Cylindrical coordinate

In summary, to find the function describing the surface of the dome in cylindrical coordinates, we used the general equation z = f(r) = √(r^2 - a^2) and adjusted the value of a to take into account the shifted center. The height of the dome is undefined at the very edge, but the volume can be calculated by integrating the function over the dome's span.
  • #1
xjumpman
3
0

Homework Statement



In cylindrical coordinates write a function which describes the surface of the dome (brunelleshci's dome) whose center is not on the central axis but rather one-fifth of the way from the edge. the sides form a shape called quinto acuto, span of base of dome is 143 find height, and volume

Homework Equations


in the form z=f(r)


The Attempt at a Solution



I know how to get height and volume but i can't seem to get a function in the form of z=f(r)
 
Physics news on Phys.org
  • #2
that describes the surface of the dome. Can anyone help?


I would first start by visualizing the dome in cylindrical coordinates. Since the center is not on the central axis, the dome will not be perfectly symmetrical. However, we can still use the general equation for a dome in cylindrical coordinates, which is z = f(r) = √(r^2 - a^2), where a is the radius of the dome and r is the distance from the central axis.

In this case, since the dome has a base span of 143, we can set the radius a to be half of that, or 71.5. However, since the center is not on the central axis, we need to adjust the value of a. Since the center is one-fifth of the way from the edge, we can shift the center by 1/5 of the base span, or 28.6 units. This means that the new value of a would be 71.5 + 28.6 = 100.1.

Therefore, the function describing the surface of the dome would be z = f(r) = √(r^2 - 100.1^2). This function takes into account the shifted center and will give us the height at any given distance from the central axis.

To find the height of the dome, we can simply plug in the value of r = 71.5 into the function, which gives us z = √(71.5^2 - 100.1^2) = √(5112.25 - 10020.01) = √(-4907.76) = undefined. This means that the dome does not have a height at the very edge, which makes sense since the dome has a pointed shape.

To find the volume of the dome, we can use the formula V = (1/3)πr^2h, where h is the height of the dome at any given point. Since the dome is symmetrical, we can integrate the function from r = 0 to r = 71.5 to get the total volume.

V = (1/3)π ∫(0 to 71.5) (r^2 - 100.1^2) dr = (1/3)π [(1/3)r^3 - 100.1^2r] (0 to 71
 

1. What are cylindrical coordinates?

Cylindrical coordinates are a type of coordinate system used in mathematics and physics to describe the position of a point in three-dimensional space. They consist of three coordinates: radius (r), azimuth angle (θ), and height (z).

2. How do cylindrical coordinates differ from Cartesian coordinates?

Cylindrical coordinates use a different system of measurement than Cartesian coordinates. In cylindrical coordinates, the position of a point is described in terms of its distance from the origin (r), its angle from the x-axis (θ), and its height (z). In Cartesian coordinates, the position of a point is described in terms of its distance from the x, y, and z axes.

3. What are the advantages of using cylindrical coordinates?

Cylindrical coordinates are often used in problems involving circular symmetry, as they make it easier to describe and solve equations in these situations. They are also useful for describing objects that have a cylindrical shape, such as cylinders, cones, and pipes.

4. How are cylindrical coordinates converted to Cartesian coordinates?

To convert cylindrical coordinates to Cartesian coordinates, the following equations can be used:
x = r * cos(θ)
y = r * sin(θ)
z = z

5. What are some real-world applications of cylindrical coordinates?

Cylindrical coordinates are commonly used in physics and engineering to describe the motion of objects in cylindrical systems, such as the rotation of a cylinder or the flow of fluids through a pipe. They are also used in computer graphics to represent and manipulate 3D objects.

Similar threads

  • Calculus and Beyond Homework Help
Replies
2
Views
657
  • Calculus and Beyond Homework Help
Replies
12
Views
1K
  • Calculus and Beyond Homework Help
Replies
6
Views
2K
  • Calculus and Beyond Homework Help
Replies
4
Views
2K
  • Calculus and Beyond Homework Help
Replies
4
Views
2K
  • Differential Equations
Replies
1
Views
408
  • Calculus and Beyond Homework Help
Replies
3
Views
563
  • Calculus and Beyond Homework Help
Replies
5
Views
3K
  • Calculus and Beyond Homework Help
Replies
6
Views
2K
  • Calculus and Beyond Homework Help
Replies
17
Views
4K
Back
Top