Recent content by absolutezer0es

The only way I can think of to eliminate R by dotting the entire equation with a vector is something that is perpendicular to it. In that case, would vector uBC work? My confusion then is with vector P. We've already defined vector P as vector P = P(uBC). Would the equation then become...

Homework Statement Bead B has negligible weight and slides without friction on rigid fixed bar AC. An elastic cord BD has spring constant k = 3 N∕mm and 20 mm unstretched length, and bead B has a force of magnitude P in direction BC. If bead B is positioned halfway between points A and C...

What do you mean by "it's"? The reaction rate doesn't increase by a factor of 8?

Ah, I see. The concentration of both would be 2M, so substituting would give me: rate = 8k[A2]2][B2] Thanks for the help!

The question is: The rate equation for the reaction A2 + B2 -> 2C (all gases) is rate = k[A2]2[B2]. If the gaseous reaction misture is compressed to half its original volume, by what factor will the reaction rate change. Assume temperature is constant. My thoughts are that the reaction rate...

So what does the 150 mean? Does it have anything to do with the problem?

I'm still lost. The field at x=0? There are an infinite number of points on x=0, depending on y and z, no? Same at x=0.01. I mean, the answer is 3.5x10^-4, according to my text. I substituted 0.01m into the expression and multiplied by (0.01)^2. Don't have a clue why though. What happened to...

Why aren't they the same? Isn't it a cube? Maybe I don't understand the expression (350x + 150)i like I think I do. Does the expression mean 350x on the way in and 150 on the way out?

Homework Statement A 1x1x1 cm box with edges aligned in the xyz-axes is in the electric field E = (350x + 150)i N/C, where x is in meters. What is the net electric flux through the box? Homework Equations flux = ExAx + EyAy + EzAz The Attempt at a Solution I substituted into the formula...

For the first, I've got nothing. Generically, I developed: Q = (16*pi*epsilon-naught*m*r^3)/(eT^2) I don't think this is it. I solved for T then and got 7.35x10^-8, but I don't think I'm on the right track. For the second, I found all sorts of kinematic values - can't connect them to q...

Here are two problems, both of which I'm not really sure where to start. The simpler (?) one first: A 1.10-mm-diameter glass sphere has a charge of +1.10 nC. What speed does an electron need to orbit the sphere 1.80mm above the surface? I thought of using v = (2*pi*r)/T because it is circular...

When I replied, I realized I made a mistake, like you said. It's not r, but rather r/2! I was able to boil down the equation to: (sinθ)^2*(tanθ) = kq^2/(4mg) I'm pretty sure you can't boil it down anymore than that, so I used my old grapher to find the intersection point between both...

Ah, yes ... a little clearer now. So sinθ = r/1 = r. Alright let me run with that. Let's see if I can get it now. Thanks for the nudge!

Two m = 6.0g point charges on 1.0-m-long threads repel each other after being charged to q = 120nC , as shown in the figure. What is the angle θ? You can assume that θ is a small angle. Hopefully the image will work. I feel like something is missing. I've gotten 7.4 and 3.4 degrees...