Recent content by Alameen Damer

Homework Statement A particle travels 27 degrees to the y axis, a magnetic field travels parallel to the y axis. In which direction is the magnetic force. Homework Equations Thumb=direction of q Fingers=direction of field palm=direction of force The Attempt at a Solution Basically how do I...

Yes the gravity pulling the balls down. However, how would i write this gravity, it has me confused. Does the angle play a part?

Two pith balls, each with a mass of 5.00g, are attached to non-conducting threads and suspended from the same point on the ceiling. Each thread has a length of 1.00m. The balls are then given an identical charge, which causes them to separate. At the point that the electrical and gravitational...

Which triangle? If you mean the one formed by the refracted ray, it is not a right angle triangle.

That is a page from my textbook. The book mentions that the angle of incidence on the right side when added with the angle of the refraction equals 60 degrees. Why is that?

Ok, are the directions of the magnetic field around the rectangle wrong?

Near the long wire, then it must be acting downwards correct?

Why are they in opposite directions? Does that not fit the right hand rule?

What I did was: Let mE be mass of Earth Let mM be mass of the moon Let mR be mass of the rocket GmEmR/r^2=GmMmR/(3.8x10^8-r)^2 (3.8x10^8-r)^2(GmEmR)=r^2(GmMmR) G and MR cancel (3.8x10^8-r)^2(mE)=r^2(mM) (5.926x10^24)r^2-4.56x10^34r+8.664x10^41=0 I then used the quadratic formula to solve...

Distance/radius so its in m, and I got the answer eventually having to use the quadratic formula.

Homework Statement Homework Equations Right hand rules The Attempt at a Solution Am i correct for a? I drew my interpretations of the magnetic field around each section. For b) am i correct to think the internal net force in the rectangular wire is 0, and the only force acting on it is that...

Homework Statement Homework Equations fg=Gm1m2/r^2 The Attempt at a Solution Let FgE be the force of gravity of Earth, and FgM be force of gravity of the moon. We need a net gravitational force of 0 N. So: FgE-FgM=0 FgE=FgM Can someone attempt to solve this and see if the answer matches...

Ok so the forces of gravity must cancel out: FgE=FgM 9.8m=gMm gM must equal 9.8 9.8=Gm1/r^2 r=root(Gm1/9.8) r=709685 Shouldn't that be the answer? As at that distance the g of the moon equals 9.8?

Do i make it so the forces of gravity equal to 0 or the accelerations of gravity equal to 0

Homework Statement Homework Equations Fg=Gm1m2/r^2 g=Gm/r^2 The Attempt at a Solution I am having trouble finding a way to start. I can't set the g to 0 because that would not let me solve for radius.