Recent content by bigboss

thanks for the notice, edited it, and stil not getting the correct answer

heat lost = heat gained or m1 * s1 * t1 + m2 * s2 * t2 + m3 * L = m1 * s1 * tf + m2 * s2 * tf + m3 * s3 * tf solving the above equation for t2 we get t2 = (m1 * s1/m2 * s2) * (tf - t1) + (m3/m2 * s2) * (s3 * tf - L) m1 = 11 g = 11 * 10^-3 kg s1 = 900 J/kg/K t1 = 200 oC = (200 + 273) K = 473 K m2...

Homework Statement 8.0 g of aluminum at 200 C and 22 g of copper are dropped into 55 cm^3 of ethyl alcohol at 15 C. The temperature quickly comes to 28 C. What was the initial temperature of the copper?Homework Equations The Attempt at a Solution tried using calorimetry equations, not getting...

yea, i took that into account, so i did heat loss=heat gained, and the heat lost was by the aluminum, and i know the ethyl alcohol gained heat, but I am not sure what side the copper would go on

i converted everything and got this formula m1 * s1 * t1 + m2 * s2 * t2 + = m1 * s1 * tf + m2 * s2 * tf + m3 * s3 * tf m1= aluminum m2=coppper m3=ethtyl alcohol, i just can't get the write answer.

Homework Statement What is the initial temperature of copper if, 11 g aluminum at 200 C and 21 g of copper are dropped into 46 cm^3 of ethyl alcohol at 15 C. The final temperature of the system is 22 C. Homework Equations Q=McT The Attempt at a Solution My work ...

therefore, force does not change? A?

so it would be the bottom of the brick, because it has the most depth, thus the most pressure

depth

Homework Statement Consider a brick that is totally immersed in water. The long edge of the brick is vertical. The pressure on the brick is A)greatest on the sides of the brick. B)greatest on the bottom of the brick. C)greatest on the face with largest area. D)greatest on the top...

then the weight would be the same

i am still not understanding this, what would be the answer?

so if the mass does not change, what does that mean?

Homework Statement In England in the Middle Ages an extensive system of canals was used for transportation. Some of these canals crossed over canyons by flowing over bridges (viaducts). Suppose that a heavily loaded barge crossed over such a waterway bridge. A)The force on the bridge would...

since it is a right angle, one car is going 13 m/s right, while the other is going 13m/s up so there is a 1:4 ratio of mass x component) m1v1+m2v2=(m1+m2)v 1(13)+(4*0)=(1+4)V 13/5= vx vx=2.6 m/s y component) m1v1+m2v2=(m1+m2)v...