Recent content by cdbowman42
-
C
Spring Pull Q1: Bob's End Moves 20cm
1. The left end of a spring is attached to a wall, When Bob pulls on the right end with a 200N force, he stretches the spring my 20cm. The same spring is then used for a tug-of-war between Bob and Carlos. Each pulls on his end of the spring with a 200N force. How far does Bob's end of the spring...- cdbowman42
- Thread
- Pull Spring
- Replies: 1
- Forum: Introductory Physics Homework Help
-
C
Conservation of Energy and ball problem
[b]1.Ball 1 with an initial speed of 14 m/s has a perfectly elastic collision with Ball 2 that is initially at rest. Afterward, the speed of Ball 2 is 21 m/s. What will be the speed of Ball 2 if the mass of Ball 1 is doubled. [b]2. conservation of momentum: m1(v1i)=m1(v1f)+m2(v2f)...- cdbowman42
- Thread
- Ball Conservation Conservation of energy Energy
- Replies: 3
- Forum: Introductory Physics Homework Help
-
C
Force, Torque and Angular Acceleration Problem
Unless there is a way to get 9.9 N somehow?- cdbowman42
- Post #9
- Forum: Introductory Physics Homework Help
-
C
Force, Torque and Angular Acceleration Problem
Ok well thanks!- cdbowman42
- Post #8
- Forum: Introductory Physics Homework Help
-
C
Force, Torque and Angular Acceleration Problem
Impulse isn't even covered that far into the book, so I don't think that's the way to go. I think we may be missing something.- cdbowman42
- Post #6
- Forum: Introductory Physics Homework Help
-
C
Force, Torque and Angular Acceleration Problem
[b]1. A man sharpens a knife by pushing it against the rim of a grindstone. The 30-cm diameter stone is spinning at 200 rpm and has a mass of 28 kg. The coefficient of kinetic friction between the knife and the stone is 0.20. If the stone loses 10 % of its speed in 10s of grinding, what is the...- cdbowman42
- Thread
- Acceleration Angular Angular acceleration Force Torque
- Replies: 8
- Forum: Introductory Physics Homework Help
-
C
Angular Momentum/Impulse Problem
Thanks! that's all I needed!- cdbowman42
- Post #3
- Forum: Introductory Physics Homework Help
-
C
Angular Momentum/Impulse Problem
[b]1. A 1.8 kg, 20 cm diameter turntable rotates at 160 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diagonal, and stick. What is the turntable's angular velocity, in rpm, just after this event? [b]2. Angular...- cdbowman42
- Thread
- Angular
- Replies: 4
- Forum: Introductory Physics Homework Help
-
C
Torque, Rotation, Pulley problem
Ok that worked. Now, is there an easier way to solve this?- cdbowman42
- Post #9
- Forum: Introductory Physics Homework Help
-
C
Torque, Rotation, Pulley problem
Ok here is my new approach. alpha=angular acceleration r-radius T=Tension M=mass of pulley m1=1.5 kg block m2=2.5 kg block a=acceleration of blocks alpha=Net Torque/I =T1r-T2r/.5Mr^2 =r(T1-T2)/(1/2)Mr^2 alpha =2(T1-T2)/Mr acceleration is in the negative direction...- cdbowman42
- Post #7
- Forum: Introductory Physics Homework Help
-
C
Torque, Rotation, Pulley problem
Ok so the tensions in each side are different. But are the accelerations of both blocks the same?- cdbowman42
- Post #6
- Forum: Introductory Physics Homework Help
-
C
Torque, Rotation, Pulley problem
But assumimg the rope is massless and the pulley is frictionless, wouldn't the tension in the rope be equal to the weight of the blocks?- cdbowman42
- Post #3
- Forum: Introductory Physics Homework Help
-
C
Torque, Rotation, Pulley problem
[b]1. A 2.5 kg block and a 1.5 kg block are attached to opposite ends of a light rope. The rope hangs over a solid frictionless pulley that is 30 cm in diameter and has a mass of .75 kg. When the blocks are released, what is the acceleration of the lighter block. Ok, the book says 2.2m/s^2...- cdbowman42
- Thread
- Pulley pulley problem Rotation Torque
- Replies: 8
- Forum: Introductory Physics Homework Help
-
C
Gravitational torque about a point on a rod
[b]1. A 2.0 kg uniform, horizontal rod is 1 m in length. What is the gravitational torque about the point A that is 25 cm from the left end of the rod. [b]2. T=Fr F=mg T=mgr [b]3. The center of gravity of the rod is directy at its center, so is therefore 25 cm from the...- cdbowman42
- Thread
- Gravitational Point Rod Torque
- Replies: 1
- Forum: Introductory Physics Homework Help