Recent content by chronicals

Can you show your calculations or explanations how you solve this problem?

[PLAIN]http://img253.imageshack.us/img253/4029/eqn464.gif Am i use this equation?

i think finger may be modeled as semi-infinite medium, initially at a uniform temperature 37°C, anybody help me overcome this problem

h is convection heat transfer coefficient. finger can be modeled as a cylinder, but what calculations i should do?

Homework Statement I must solve this problem, please help me, which equations i should use? Most of us have passed our finger through a 800C candle flame and know that if we limit exposure to about 0.25 s, we will not be burned. Why not? Show all the calculations that support your answer...

i think working with volume rate is useless

Homework Statement For turbulent flow in a smooth, circular tube with a radius R, the velocity profile varies according to the following expression at a Reynolds number of about 10^5. Vx= Vxmax * [(R-r)/R)]^(1/7) where r is the radial distance from the center and Vmax the maximum...

I want to compute x within 0.1% relative error with Simpson method, these are my m-files. Which command i should add for this? function simps(a, b, n) %simps(a, b, n) approximates the integral of a function f(x) in the %interval [a;b] by the composite simpson rule %n is the number of...

Can you give me the function which i should integrate, the problem is very complex and difficult to solve for me

Homework Statement The relative velocity of two small spheres subjected to a constant force in a liquid is given by u = uo/f where f is the drag correction factor and u0 is the relative velocity of the spheres when they are far apart. The drag coefficient factor, f, is a function of (r/a)...

If I use err(iter), I have an infinite loop, so I use abs(fnnew). These are my results: iteration n relative approximate error 1 62.759758 8.349685 2 62.689966 8.470309 3 62.691698 0.002762 4 62.691697 0.000001 nnew = 62.6917 iter = 4 how can second iterations' relative...

I rearranged my m-file and i solved infinite loop problem but i think i have mistaken at calculating absolute relative approximate error at the end of each iteration, i think this command is wrong: err(iter)=(abs((nnew-n2)/nnew))*100; How can i fix this error calculation problem...

I try to solve this equation with secant method in MATLAB. fn=40*n^1.5-875*n+35000 my initial guess is n1=60; n2=68; I want to find root and absolute relative approximate error at the end of each iteration. I have an infinite loop. Can you help me repair my file? This is my m-file...

I find lecture notes: ''the absolute relative approximate error'' = (( x_present - x_previous ) / x_present )*100

I'm a bit confused, i have a question, it asks me to find ''the absolute relative approximate error'' at the end of each iteration. What's the formula of ''the absolute relative approximate error''?