Recent content by Cocoleia

I have always seen this problem formulated in a well that goes from 0 to L I am confused how to use this boundary, as well as unsure of what a dimensionless hamiltonian is. This is as far as I have gotten

I am given this Hamiltonian: And asked to diagonalize. I understand how we do such a Hamiltonian: But I don't understand how to deal with the extra term in my given Hamiltonian. Usually we use To get

Thank you for such a detailed explanation

I have been trying to use what you mentioned in your previous two comments. Thank you, I think it was very useful. Do you mind looking over what I did to see if it makes sense? Thank you for your input.

I am quite confused, as I start this question. I can easily find the following when searching up Planck's law: However, this is not u. My prof is quite unclear and sometimes chooses his own variables as he sees fit, so i am not sure if this would be equivalent to what he is looking for u(λ)dλ...

Homework Statement Homework EquationsThe Attempt at a Solution I have posted the whole solution so it is more complete, but I really only need help with part c (I think) My output power is higher than my input power, I'm not sure where I'm going wrong

Ok so it is not enough to say For a simple cubic lattice, it is clear that the nearest neighbor distance is just the lattice parameter, a. I would have to derive the energy equation that is given to me and set =0

That's the entire problem copied and pasted from the assignment. I'm not sure what you mean by what do I take the derivative of ?

Homework Statement The energy per ion in for CsCl is nearly – (αe 2 /(4πε0)) + 8Ae -(R/ρ) , where α is the Madelung constant and A = 5.64 x 103 eV and ρ = 0.34 Å. Calculate the nearest neighbour equilibrium distance. Homework Equations alpha = 2 ln 2 The Attempt at a Solution I think that...

Wait, how did you find 15cm ?

Thanks for your help. I would love to ask my colleagues for help but everyone is gone this ... just me and my physics. So I turn to Physics Forums o0)

Based on this principle

Yes I see this... So I have derived / found the equations for momentum of two body decay: Then in the lab frame Now, I also see that I just don't now how to piece this together to get the height at which the particle hits the detector. Somehow use this last formula, tan(theta') * 0.4 will...

The thing is I'm very new to this and I don't understand what relationship i am supposed to find between the angle, momentum and the position where my particle will hit on the detector. Will it involve angular momentum ?

Yes, it's just a first exercise to introduce me to the material and the software. eventually it will be a monte carlo simulation... right now I'm just trying to understand the problem and do some basic C++ coding.