Recent content by DANIELLYMA

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    Plane Mirror Problem: Solve Intensity Using I = Ps/(4*PI*r^2)

    r is the radius of the source, how do I take into account the the 3d distance from the screen?
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    Plane Mirror Problem: Solve Intensity Using I = Ps/(4*PI*r^2)

    oops thanks for pointing out the typo but I still don't understand what power has to do with this problem.
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    Plane Mirror Problem: Solve Intensity Using I = Ps/(4*PI*r^2)

    I'm having problems doing the problem below. The equation in the hint is: I = Ps/(4*PI*r^2) which I have not clue how it relates to this question except for that it's an equation for intensity. I know that there will be a image produced a distance d behind the mirror, so there will be another...
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    Really hard Volume Question.

    Really hard Volume Question. URGENT! Can someone help me with this question? I don't know where to begin. I don't want the answers, just hints in the right direction *edit* can a mod please fix the topic title? It's supposed to read 'Really hard Volume Question. URGENT!' << Done. >>...
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    Epotential of Point Charges - Really Hard Conceptual Problem

    yea that's right I think, Vr2 would equal to kQ/r but I'm also stumped on how it is simplied to the final answer.
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    Work Done by moving point charge

    Edit: I reuploaded the picture, thanks for your replies
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    Work Done by moving point charge

    Hi I think I figured it but I'm not sure. Here's the problem: How Much Work In Fig. 25-34, how much work is required to bring the charge of +5q in from infinity along the dashed line and place it as shown near the two fixed charges +4q and –2q? Take distance d = 1.40 cm and charge q = 1.6 ×...
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    How Do You Calculate Impulse and Force in a Rear-End Collision?

    A 75 kg man is sitting in his car at rest at the stoplight. He is rear-ended by another car and is accelerated to 3.0 m/s in 0.2s. What is the impulse on the man and his car? I found the impuse on the man which was: I = m(change v) = 75(3.0 -0) = 225 Ns I found the Net force on the...
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    Direction of Reaction Force on Beam in Torque Problem

    My teacher told me it wasn't in equilibrium since there is a torque.
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    Direction of Reaction Force on Beam in Torque Problem

    I don't undestand what you mean. The beam is not in equilibrium, and I know torque caused by the wall is zero, but I was wondering what's the direction of the force exerted by the wall.
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    Direction of Reaction Force on Beam in Torque Problem

    Here's an image of the problem I trying to do. http://img339.imageshack.us/img339/1765/torquequestionqv0.th.gif I'm wondering if there is a force exerted by the wall on the beam, and if so in which direction? I think it's pointed upward to the right, but I'm not too sure. Any help...
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    Estimating Jet Speed Using Sound and Light

    I think it can be figured out because as I previously posted, my teacher hinted at using the speed of sound, speed of light, and a stop watch.
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    Estimating Jet Speed Using Sound and Light

    Thanks for the answer, but is there a way to estimate the speed of the jet?
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