Recent content by ian_durrant
-
I
High School Canceling out low frequencies noises (subwoolfers)
That sounds by the far the most practical way to solve this delema. haha thanks.- ian_durrant
- Post #9
- Forum: Other Physics Topics
-
I
High School Canceling out low frequencies noises (subwoolfers)
haha i knew someone would bring up the police so there doesn't really sound like much that can be done besides soundproofing my walls. are there any type of smaller headphones that do noise cancellation?- ian_durrant
- Post #6
- Forum: Other Physics Topics
-
I
High School Why Do Solutions Sometimes Differ from Absolute Values?
simply put i believe when you have an the absolute value is how far the number is away from zero on the number line. So if you had the absolute value of -4, it would be four. try this for further understanding, including the real mathmatical definition...- ian_durrant
- Post #2
- Forum: Linear and Abstract Algebra
-
I
High School Canceling out low frequencies noises (subwoolfers)
Here's an interesting problem that might be best solved by physics: Lets say your neighbors insist on using a loud subwoolfer late at night, it travels through your appartment walls and keeps you up all night. What would be a good way to cancel out the noise, other than earphones?- ian_durrant
- Thread
- Frequencies
- Replies: 12
- Forum: Other Physics Topics
-
I
Force's and Newton's Laws of Motion
ahhh i see it now ok i redefined variables: F(m) = force from moon F(e)= force from earth G= gravitational constant x= distance where force of moon is greater than earth m(m)= mass of moon m(2)= spaceship Gives me... F(m)= Gm(m)m(2)/x F(e)= G81.4m(m)m(2)/ (3.85*10^8-x)^2 Now...- ian_durrant
- Post #8
- Forum: Introductory Physics Homework Help
-
I
Force's and Newton's Laws of Motion
Ok I took the suggestion of solving for x and here's what I did: x= distance from center of Earth where moon exerts more force -F(1)= G81.4m/x (this is the force from the Earth, negative since its working in the opposite direction from the moon) F(2)= Gm/(3.85*10^8-x) force that the...- ian_durrant
- Post #6
- Forum: Introductory Physics Homework Help
-
I
Force's and Newton's Laws of Motion
Homework Statement A spacecraft is on a journey to the moon. At what point, as measured from the center of the earth, does the gravitational force exerted on the spacecraft by the Earth balance that exerted by the moon? This point lies on a line between the centers of the Earth and the...- ian_durrant
- Thread
- Laws Laws of motion Motion Newton's laws
- Replies: 8
- Forum: Introductory Physics Homework Help
-
I
What is the final speed of the ball when the goalie catches it?
Ahhh i see it now, the height wasn't even needed in this problem, thanks for the tip.- ian_durrant
- Post #3
- Forum: Introductory Physics Homework Help
-
I
What is the final speed of the ball when the goalie catches it?
[SOLVED] Kinematics in 2-dimesions Homework Statement A soccer player kicks the ball toward a goal that is 25.0 m in front of him. The ball leaves his foot at a speed of 19.2 m/s and an angle of 65.8 ° above the ground. Find the speed of the ball when the goalie catches it in front of the...- ian_durrant
- Thread
- Kinematics
- Replies: 2
- Forum: Introductory Physics Homework Help
-
I
Kinematics in two dimensions problem
so it would be a logical assumption that g=0 in the x direction, correct? so an equaiton would look something like this? 195=V(0)(3.13)+(1/2)(0)(3.13)^2 195=3.13V(0) V(0)= 62.3 m/s?- ian_durrant
- Post #5
- Forum: Introductory Physics Homework Help
-
I
Kinematics in two dimensions problem
I'm a little confused, wouldn't V=0 on the x-axis if the car had stopped/crashed, but on the Y-axis there still is the force of gravity. Or are you saying that my time i computed for the Y values won't work for my X values?- ian_durrant
- Post #3
- Forum: Introductory Physics Homework Help
-
I
Kinematics in two dimensions problem
[SOLVED] Kinematics in two dimensions problem Homework Statement Chapter 3, Problem 20 Incorrect. A car drives horizontally off the edge of a cliff that is 48.1 m high. The police at the scene of the accident note that the point of impact is 195 m from the base of the cliff...- ian_durrant
- Thread
- Dimensions Kinematics Two dimensions
- Replies: 5
- Forum: Introductory Physics Homework Help
-
I
How Do You Calculate the Time Ratio for Two Jumping Heights on a Trampoline?
thanks for all the help everyone- ian_durrant
- Post #5
- Forum: Introductory Physics Homework Help
-
I
How Do You Calculate the Time Ratio for Two Jumping Heights on a Trampoline?
good point about the ratio, but I'm still confused why I'm going to have a negative number for t, or would this not matter anyways?- ian_durrant
- Post #3
- Forum: Introductory Physics Homework Help
-
I
How Do You Calculate the Time Ratio for Two Jumping Heights on a Trampoline?
[SOLVED] Acceleration/Velocity Problem Homework Statement Two students, Anne and Joan, are bouncing straight up and down on a trampoline. Anne bounces 2.61 times as high as Joan does. Assuming both are in free-fall, find the ratio of the time Anne spends between bounces to the time Joan...- ian_durrant
- Thread
- Replies: 4
- Forum: Introductory Physics Homework Help