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LindseyM2011
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In equations dealing with absolute value sometimes the answer to the equation does not coorospond with the absolute value. Why is this?
Why Do Solutions Sometimes Differ from Absolute Values?
- Thread starter LindseyM2011
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- Absolute Absolute value Value
This is the question,
I understand the concept, in ##\mathbb{Z_n}## an element is a is a unit if and only if gcd( a,n) =1.
My understanding of backwards substitution,
...
i have using Euclidean algorithm,
##471 = 3⋅121 + 108##
##121 = 1⋅108 + 13##
##108 =8⋅13+4##
##13=3⋅4+1##
##4=4⋅1+0##
using back-substitution,
##1=13-3⋅4##
##=(121-1⋅108)-3(108-8⋅13)##
...
##= 121-(471-3⋅121)-3⋅471+9⋅121+24⋅121-24(471-3⋅121##
##=121-471+3⋅121-3⋅471+9⋅121+24⋅121-24⋅471+72⋅121##...
##\textbf{Exercise 10}:##
I came across the following solution online:
Questions:
1. When the author states in "that ring (not sure if he is referring to ##R## or ##R/\mathfrak{p}##, but I am guessing the later) ##x_n x_{n+1}=0## for all odd $n$ and ##x_{n+1}## is invertible, so that ##x_n=0##"
2. How does ##x_nx_{n+1}=0## implies that ##x_{n+1}## is invertible and ##x_n=0##. I mean if the quotient ring ##R/\mathfrak{p}## is an integral domain, and ##x_{n+1}## is invertible then...
The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho.
In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states
"Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels).
Also in the reference url page above, the authors present two...
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