Recent content by marcom

  1. M

    I Contour integral from "QFT for the gifted amateur"

    Perhaps because: ##\int_{-\infty}^{0} f(x)dx##=##-\int_{0}^{-\infty} f(x)dx##=##-\int_{0}^{+\infty} f(-x)d(-x)## ?
  2. M

    I Contour integral from "QFT for the gifted amateur"

    Sorry to talk again about this but normally exchanging the limits of integration only introduces a minus sign ∫ ab=-∫ba And the result wouldn't be the same, so I don't understand why the substitution p -p works. (And to be precise in the book they calculate the integral from infinity to I am...
  3. M

    I Contour integral from "QFT for the gifted amateur"

    OK, thanks a lot for your help!
  4. M

    I Contour integral from "QFT for the gifted amateur"

    I obtain: ∫d|p||p| e-it (√|p| 2 + m 2)(ei|p||x|+e-i|p||x|)
  5. M

    I Contour integral from "QFT for the gifted amateur"

    Thanks but I didn't understand
  6. M

    I Contour integral from "QFT for the gifted amateur"

    Hi, Could you please help me understand the following example from page 76 of "QFT for the gifted amatur"? I can't see how the following integral becomes Thanks a lot
  7. M

    Infinitesimal transformation of a field

    Hi, Could you please explain me why, under the transformation of a complex valued field Φ→eiαΦ, for an infinitesimal transformation we have the following relation? δΦ=iαΦ Thanks a lot
  8. M

    Quantum QFT books in order of difficulty

    Hi, I'd like to ask you if you could write a list of QFT books in order of increasing difficulty. Thanks!
  9. M

    Contour integral example from "QFT for the gifted amatueur"

    Hi, I've never studied compex analysis before but I am trying to understand this example from "QFT for the gifted amatur". I don't understand why the residue at the pole is e-iEp(t-t')e-e(t-t'). How did the find e-e(t-t')? Thanks.
  10. M

    Prerequisites for Quantum Field Theory (QFT)

    https://fliptomato.wordpress.com/2006/12/30/from-griffiths-to-peskin-a-lit-review-for-beginners/
  11. M

    Particle in a box - Momentum and Energy

    OK, it's an eigenfunction of p2, isn't it? ψn=(√2/a) sin (nπx/a) (d2/dx2) sin (nπx/a) = -(nπ/a)2 sin (nπx/a) p2ψn=-(iħ)2 (nπ/a)2ψn=(nπħ/a)2ψn
  12. M

    Particle in a box - Momentum and Energy

    I found a page in the same site that proves my point: "the momentum is equally likely to be in either direction. The magnitude of the momentum is a constant, since this is a state with fixed energy, and " http://physicspages.com/2012/09/13/infinite-square-well-momentum/
  13. M

    Particle in a box - Momentum and Energy

    I think that my question is wrong, the momentum is quantized actually. En=n2π2ħ2/2mL2 Pn2=2mEn=2mn2π2ħ2/2mL2 Pn=±nπħ/L
  14. M

    Particle in a box - Momentum and Energy

    Hi, I have a problem understanding the particle in a box (V=0 inside, V=∞ outside), how is it possible that momentum can vary continuously while the energy spectrum is discrete? Aren't they related by E=p2/2m? What I am missing? Thanks!
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