Recent content by Mindstein

Ah great, thanks mfb. I appreciate it.

Homework Statement On the utterly unrealistic assumption that there are no other charged particles in the vicinity, at what distance below a proton would the upward force on an electron equal the electrons weight?Homework Equations I used Newtons universal law of gravitation as well as Coulombs...

Thanks tiny-tim and oli4, you all sure do know how to get a brother past his problems!

Homework Statement Is the set of a single element {e} with the multiplication law ee = e a group?Homework Equations none.The Attempt at a Solution Yes, it is a group. But that is not my question. My question is how do you ask the question? If I were face to face with you and wanted to ask you...

I think I may be over-thinking this as I have had one formal course in QM and an independent study course in QM, but any help is MORE THAN GREATLY APPRECIATED! Homework Statement Prove that |-V> = -|V> Homework Equations He instructs us to begin with |V> + (-|V>) = 0|V> = |0>...

Ahhh okay, so what I would want to say is that y^2 \leq\frac{y^3}{x^2+y^2}\leqx2+y2 ?

Yes, I am trying to determine the limit as x,y approaches the origin. The problem is that I have no clue how to apply the squeeze theorem. I can't find any good sites on it.

Homework Statement Evaluate the limit of the function f(x,y) = \frac{y^3}{x^2+y^2} Homework Equations The Attempt at a Solution Well, I approached this problem using the multiple-path method and found the following: \stackrel{lim}{x\rightarrow 0} \frac{y^3}{x^2+y^2} = y...

Homework Statement A 9.00-kg hanging object is connected, by a light, inextensible cord over a light, frictionless pulley, to a 5.00-kg block that is sliding on a flat table. Taking the coefficient of kinetic friction as .200, find the tension in the string Homework Equations F = ma...

I can not thank you enough! Thank you very much!

Homework Statement A placekicker must kick a football from a point 36.0 m (about 40 yards) from the goal, and half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 20.0 m/s at an angle of 53.0º to the horizontal...

He found it by using Fk1 = Uk(mu sub 'k')N with N = mg (but in the opposite direction) Force of Friction of Block 1 = (.1)(12.0 kg)(9.8 m/s²) = 11.76 N Force of Friction of Block 2 = (.1)(18.0 kg)(9.8 m/s²) = 17.64 N

I know this is an old thread, but why is 14.7 negative in your final quadratic equation?