Recent content by nikkor180
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Undergrad Space-time curvature and the fabric of space
Greetings: I watched several videos describing so-called "empty space" as being permeated with fields (electron field, quark field, etc.). Is it possible that it is actually these fields that curve about large masses and that the trajectory of light and matter curve because they follow the...- nikkor180
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- Curvature Fabric Fabric of space Space Space-time Space-time curvature
- Replies: 13
- Forum: Special and General Relativity
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Graduate Einstein's Definition of Mass: m = E/c^2
Greetings: I hope I am posting in the appropriate forum. I understand that in special relativity, Einstein expressed e = mc^2 as m = e/c^2. Is this his way of defining mass? If not, can you explain how he came to this conclusion?- nikkor180
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- Replies: 3
- Forum: Special and General Relativity
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Undergrad Gravity in General Relativity: Explaining Acceleration
Greetings: I can understand that an object's trajectory curves about a greater mass (e. g., satellite in Earth's orbit). The spacetime is curved via the great mass and the moving object simply follows the curvature. My problem is this: Why does a stationary object at a short distance from...- nikkor180
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- General General relativity Gravity Relativity
- Replies: 9
- Forum: Special and General Relativity
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MHB Why Do We Use The with Calculus?
Deveno: Thank you so much for responding to my post. That was quite a nice dissertation! Best wishes, Rich -
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MHB Why Do We Use The with Calculus?
In English grammar, we typically refer to specific branches of mathematics without a prefixed article; e.g., solve using algebra, trig., etc.. By contrast, we often prefix calculus with the definite article, "the". For instance, "solve via the calculus". Can anyone explain this exception to... -
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MHB Proving No Set Contains All Sets Without Russell's Paradox
Thanks folks.- nikkor180
- Post #6
- Forum: Set Theory, Logic, Probability, Statistics
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MHB Proving No Set Contains All Sets Without Russell's Paradox
Evgeny.Makarov: Thank you for responding to my post. 1) I mean "S is an element of S" (not subset). Regarding "If X is in S for some X not=S, then S - S cannot be empty", I need to ponder that further. I will respond soon. Thanks again, Rich B. BTW, can you tell me how to access symbols...- nikkor180
- Post #3
- Forum: Set Theory, Logic, Probability, Statistics
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MHB Proving No Set Contains All Sets Without Russell's Paradox
Greetings: I am attempting to prove that no set contains all sets without Russell's paradox. What I have thus far is this: Let S be an arbitrary set and suppose S contains S. If X is in S for some X not=S, then S - S cannot be empty. But this is a contradiction; hence if S contains S, then...- nikkor180
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- Paradox Set Sets
- Replies: 6
- Forum: Set Theory, Logic, Probability, Statistics
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Undergrad Integration [ 1/(c+cos(x)) ] by dx
Greetings: If you let u = tan(x/2), then dx = 2*du /(u^2+1), sin(x) = 2u/(u^2+1), cos(x) = (1-u^2)/(1+u^2). If you substitute these values appropriately, each integral should return an inverse trig function. Regards, Rich B. -
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Undergrad Quick question about integral of (1/x)
[FONT="Verdana"]Greetings: d/dx [ln(x)] = lim(h-->0) [(ln(x+h) - ln(x)) / h] = lim(h-->0) [(1/h)*ln[(x+h)/x] = (1/x) lim(h-->0) [(x/h) ln(1+h/x)] = (1/x) lim(h-->0) [ln(1+h/x)^(x/h)] = (1/x) ln [lim(h-->0) [(1+(h/x))^(x/h)]] {from lim[f(g(x))] = f(lim[g(x)])} = (1/x) ln e... -
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Gravity: Point where Earth's Gravity and the Moon's cancel each other out?
[FONT="Verdana"]Greetings: I believe the point of interest to be none other than the center of mass which is at mer / (me + mm) meters from the Earth along the ray extending from Earth through the moon. Regards, Rich B. rmath4u2@aol.com- nikkor180
- Post #5
- Forum: Advanced Physics Homework Help
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HW Question, very simple. mass/gravity
Greetings: If acceleration due to gravity is equal for both the Earth and another planet, then, Gme / re2 = Gmp / rp2. ==> me = (re / rp)2 mp ==> me = (2rp / rp)2 (given re = 2rp) ==> me = 4mp Regards, Rich B. rmath4u2@aol.com- nikkor180
- Post #4
- Forum: Introductory Physics Homework Help
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Undergrad Evaluating Limit: x to Infinity
[FONT="Verdana"]Greetings: The previous poster was indeed correct in that the numerator's second term goes to zero. That said, the limit becomes, limit(x-->inf) [(ln(1 + 1/sqrt(2))^x) / x]. From the property log(u^n) = n*log(u), we have, limit [x*ln(1 + 1/sqrt(2)) / x] = limit [ln(1 +...