Recent content by PhysicS FAN

I guess you are right but still if we assume that there is friction between the two masses then the friction will only affect the circular motion of the cylinder. So it would be written T'-μΝ= 1/2ma where N the force between the objects and its horizontal. So T'- 0.5(13-2a)=a and so T' -...

For the non-circular object of mass m: From Newtons second law we get that F-N-T=ma where N is the force that the cylinder acts on the object. Replacing numbers: 13-N=2a. For the cylinder: From Στ=Τa(ang) we get that T'= 1/2ma or T'=a. Where T' is the friction that acts on the cylinder and we...

Well the momentum of the sphere before the collision and the momentum after create a 120 deegres angle and so the change will be the distance of the beggining of the first and the end of the last momentum arrow

The speed of the sphere after the impact will be the same since the collision is elastic and the kinetic energy remains the same. So the change of momentum will be given by the cosine law right? What bothers me is the second question about the force that acts on the sphere (which can be given by...

Thanks a lot you've been really helpful!

Well, I can't find anything that way. I think the best way to approach it is energetically since D theoritically could be found this way.

Yes I'll try that

First of all, I found a function of the distance of the object form the equivalence point in both cases. I got something like d=2d' where d is the distance at the first case and d' at the second. I did that because I wanted to find the frequency, and so first I need to find the period of...

Well there is no difference since the Kinetic energy is different, the momentum is different and that won't lead anywhere

I'm stuck I don't know how to continue. The reason is that I can not combine any equations and so I can't proceed

1. The problem statement, all variables and the known data A bullet (mass m) is shot with an initial velocity (V) towards an object with mass M=3m as shown in the picture. The energy needed to penetrate the object is 30J. The same bullet is shot with a velocity (v) heading to an identical...

Thank you for your help. (It's a Greek book the one that I saw the problem:smile:)

Homework Statement If a staight ε: y=(-λ+μ)x +2λ -μ , (where μ and λ are real numbers) passes through point A(0,1) and is parallel to an other straight lin. ζ: y= -2x + 2008 find λ and μ Homework EquationsThe Attempt at a Solution It is clear that when x=0 we know that 2λ-μ=1 which is one of...

Yeah

Sorry my fault, B is representing a point not a force. The theoritical proof is that in order for the sphere to rotate, the torque of F should be bigger than the torque of T. Its clear that both T and F are in the same distance from the center K which means we can now compare F and T as forces...