Recent content by r0306

I see what you mean now! Since current through a circuit is uniform, the number of electrons per second should not change either. Thank you!

I'm having trouble putting this in perspective. If the charges spread back out, wouldn't they just push backwards towards the x direction?

This would cause a greater potential difference between that point and the end of the circuit.

I still don't get what this entails. Does this mean that current will be less in the resistor?

Wouldn't they accumulate in the right hand wire then?

Yes. That was what I put but my answers were incorrect.

Homework Statement Homework EquationsThe Attempt at a Solution I have selected what I thought were the right choices in the original question. Resistors reduce current so electron flow should have been greater on the right. Also, the electrons flow opposite to current so potential is higher...

I got the answer. What I went wrong on was subtracting instead of adding the electric fields. The final answer should be 28.8*10^9 V/C.

The Q values were simply 1 and -1 respectively. Does this mean I should use half the distance given (2.31 mm) then? EDIT: I tried using half the distance, yielding me a value of -1.25 but the answer is still wrong.

The question is based on the image below but is not the same. The question is as follows: Assume the capacitor is charged, so that there is a charge q on the top plate and a charge -q on the bottom plate. Determine the magnitude of the potential difference across the k2 region, answering in...

That means all of the points listed are true then? I'm really uncertain about the second point.

I'm unsure if the following is true or not in the absence of external forces: Electric potential is a scalar quantity. This I know is true because there is no direction associated with potential energy. It is always possible to assign a value of zero to the electric potential at the...