From the moment the fuel finishes, only one force acts upon the rocket: gravity.
So find the the velocity the rocket possesses after those 7 seconds of propulsion and then use the constant acceleration formulae to find the height at which the rocket has v=0.
Just use Newton's Laws to know that a force corresponds to an acceleration.
As the elevator moves, a new force is exerted on the man. The direction of this force depends on the direction of motion of the elevator.
Does it make sense?
The latent heat is the amount of energy absorbed or emitted by a system during a phase transition (liquid -> solid, say) carried out at constant temperature.
You should proceed in calculating what the latent heat is in this instance; then it should be fairly obvious what to do ;)
Ok, thanks for your suggestion.
Right, I need to solve equations (1) and (3) for two omegas only. That is, two of the omegas would be zero, whilst the other non-zero.
And the sum of the omegas must always be 1.
What I've written so far in Mathematica is:
sol = NSolve[r2[z] ==...
hello, I have to solve a couple of equations on Mathematica for a project, and since they are not really working out, I wondered if you could help me out a bit.
I need to solve equation (1) (you can find the equations in the .doc attached) and plot the solution for a...
Ok, I'm given a formula for the cross section of the scattering and I've been told that the detector is a column of water of depth 10m. I need to find the probability of the scattering within the detector.
σ = E(in MeV) x 1.5x10-44 cm2
Ok, the problem is simple enough, I think. I just think I'm missing something obvious.
I have an equation involving the scale factor R(t) and need to integrate it.
I am at the first equation and need to get to the second by integrating (with respect of R, I suppose)...
Use c=νλ with the values given for the frequency and the speed of light.
(ν here is the greek letter "nu", denoting frequency)
From this, you'll find the wavelength of the wave.
Now, the waves will "hit" the wall and be reflected towards the car again, so the intereference will be costrunctive...
Because there are two capacitors in the circuit.
If you use C=C2 (1e-6), then you are just considering a circuit having *one* capacitor.
You basically need to find C to see how the capacitance is split between the two capacitors. That would also give you how the charge is split.