I believe because liquid oxygen is paramagnetic, and not ferromagnetic, it cannot be called a magnet. But this depends on your definition of a magnet. I think the official definition is that a magnet must hold a persistent magnetisation, which oxygen would not do once removed from a magnetic field.
The equation you've used is finding time, not distance.
The equation to use in this case is:
v^2 = u^2 + 2as
Where v is the final speed, u is the initial speed, a is the acceleration and s is the displacement.
Rearrange this to find s.
Remember that the driver is decelerating, so...
I'm writing up a report on an experiment I did involving liquid nitrogen.
I need to state the boiling point of liquid nitrogen (77.36K) in the report, as I've used it in calculations, but I don't know if I should get a reference for it or not. I did use a reference (Wikipedia and Google...
Never mind, I'm an idiot! I found the value for omega to be 1.3M and assumed this was the frequency, but I didn't divide it by 2 pi which would have given me the correct answer!
Thanks anyway.
Homework Statement
A resonant current of 50mA flows in a circuit consisting of a 2mH inductor, 20 ohm resistor and 0.3nF capacitor all in series. What is the applied voltage? If the current is reduced to 30mA by changing the frequency but not the voltage, find the new frequency and the phase...
You make a very good point! I somehow got it in my head that the second ball would be traveling at high speed when it hit the first. But as you've proved, it can't have a non-zero velocity if it happens at h/2.
EDIT: Disregard all of the below, see next post!
You're making innecessary assumptions here. The second ball's velocity needn't necessarily be zero at h/2. Since we're only dealing with one dimension here, there is only one possible initial speed of ball 2 that can allow it to hit ball 1 at...
The vector product will give you a vector that is perpendicular to both a and b. This should be sufficient to answer the question, I don't think you need to find another which is parallel to this vector.
It's quite hard to conceptualise but the difference can be shown by remembering that energy is a scalar quantity and momentum is a vector quantity. In a collision, due to Newton's third law of motion -- every action has an equal and opposite reaction -- the total momentum of a system is...
The amplitude is equivalent to the maximum point on the wave that a wave equation describes.
Remember that cosine (and indeed sine) functions vary between -1 and 1, so the maximum cos value you can get is 1.
So what is the maximum that E can be in that equation?
As far as I understand the question, the Earth and the moon's radii should not be added together at all. As I said in my last post, you've to do two calculations and compare them.
For the Earth calculation, m1 is 9kg (the mass), and m2 is 6*10^24kg (the earth), and r is 6.4*10^6 (distance...
No, not at all. The two radii given are for the Earth and the moon, respectively (the moon radius is expressed in terms of a ratio of the earth's). Since the question is asking you to compare two forces -- one on the Earth and one on the moon -- you need to do two calculations: one for the 9kg...
Since you're being asked to compare forces, m1 will in both cases be the 9kg block and m2 will either be the Earth or the moon.
For the r value, consider the mass of the Earth and moon to be concentrated at the centre. Consider the 9kg mass to be at the surface. The variable r is the distance...