Recent content by thaalescosta

The wire carrying the current is 8cm below the point where the net field is equal zero.

I know, but I don't see how that would help me with the visualization. I have it scaled on paper, but I still don't get why the direction of the current must go from west to east instead of the opposite

what do you mean

This is how I'm visualizing. The answer says the current flows from west to east, but I don't see how the magnetic field is being canceled by the current.

This is the question: At a certain location in the Philippines, Earth’s magnetic field of 39 µT is horizontal and directed due north. Suppose the net field is zero exactly 8.0 cm above a long, straight, horizontal wire that carries a constant current. What are the magnitude and direction of the...

You're right. My solution was making ΔA = 0 and then setting SdT = - pdV. Since S = R: - SdT = (1/V)*nRT⋅dV - dT = (1/V)*nT⋅dV (and n = 1) - dT/T = (1/V)dV - ln(T2/T1) = ln(V2/V1) - ln(2) = ln(V2/V1) 1/2 = V2/V1 V1 = 2V2 (P1⋅V1)/T1 = (P2⋅V2)/T2 (1 atm ⋅2V2)/300 = (P2 ⋅ V2)/600K P2 = 4 atm

It did not specify if the gas is mono-atomic nor did it give me the Cp or Cv values. It only asks me to find the final pressure, which is 4 atm.

Homework Statement If the Helmholtz Free Energy remains constant, estimate the final pressure of 1.0mol of an ideal gas in the following transformation: (1.0atm, 300k) → (pfinal, 600k). Given Sgas = R. Homework Equations A = U - TS dA = -SdT - pdV The Attempt at a Solution If the Helmholtz...

Hello, I'm struggling with a simple problem here. It asks me to solve the following initial value problem: So far I've calculated the integration factor μ(x) = ex-x2 and I multiplied both sides of the equation by it and got this...

Got it :) So I = ΔP = P_{f} - P_{i} = ∫Fdt, from i to f My impulse turned out to be 4/3. The mass of the particle wasn't given. I'm guessing that the answer will be in general terms. If I = m.v, then v = 3m/4 And if the maximum height is h_{max} = v²/2g then h_{max} = 9m²/32g...

Homework Statement A particle receives an impulse that lasts 1s, coming from a upwards vertical force. This force is given by the following equation: F = -8t²+8t. What is the maximum height reached by the particle?Homework Equations F = -8t²+8t The Attempt at a Solution \int(-8t²+8t)dt =...