How Does Your Weight on the Moon Compare to Earth?

Thread starter HarbingerGunn
Start date Nov 14, 2010
Tags

Mass Moon

AI Thread Summary

A person weighing 900 N on Earth has a mass of approximately 91.83 kg, calculated using the formula F=ma with Earth's gravity at 9.8 m/s². Since the moon's gravity is 1/6 that of Earth's, the weight on the moon would be significantly less. The calculation confirms that the mass remains constant regardless of location, while weight varies with gravitational force. The discussion emphasizes the distinction between mass and weight in different gravitational environments. Overall, the calculations and concepts presented are accurate.

Nov 14, 2010

HarbingerGunn

1. If a man weighs 900 N on Earth what would his mass on the moon be? Gravity on the moon is 1/6 the gravity on the Earth. (use 9.8 m/s^2)

2. F=ma

3. 900=m(9.8)
m=91.83

ans=91.83

I'm fairly certain that this is correct, i just want a little confirmation because the moon thing throws me off

Physics news on Phys.org

Nov 15, 2010

Pagan Harpoon

That is correct.

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »