Determining the saturation current

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To determine the saturation current of a GaAs LED, the user plotted current versus voltage on semi-log paper, identifying a linear segment between 1uA and 5000uA, which was later corrected to 5mA-50mA. The reverse saturation current (Is) is modeled by the equation I = Is * (e^(V/(nVt)) - 1), but this model is only valid for low forward currents. For higher currents, the LED's series resistance must be factored in to accurately assess the forward voltage. An application note was provided to guide the calculation of reverse saturation current, n, and series resistance based on the user's measurements. Accurate modeling requires careful consideration of both linear segments and ohmic losses in the LED.
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Hello all, I have a GaAs LED, and I want to determine the saturation current. I have numerous points from 0.5V-2.9V, with currents of 0.1uA-50mA. I have plotted it on semi-log paper, however, the only linear segment is from 1uA-5000uA, and then it begins to curve downwards. I used the linear segment to determine the saturation current, and the value of "n", however, they hardly describe the diode for anything else beyond this linear segment... Have I done something improper for determining these values?

Note: if I do a scatter plot in excel of all my points, the linear segment is rather from 5mA-50mA
 
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Whoops, somehow the axes were messed. Check the attached:
Also attached is the semi-log graph
 

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The reverse saturation current (Is) for a diode is typically modeled as I = Is * (e^(V/(nVt)) - 1). This model is applicable to LEDs only for very low forward currents. For forward currents above a few mA, the ohmic losses in the LED must be included to accurately model the forward voltage. You are going to need to calculate the LED series resistance based on the measurements you’ve collected.

I’ve attached an application note that shows a procedure for calculating the reverse saturation current, n, and series resistance of an LED using the forward current measurements you’ve already made.
 

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