Redhat said:
When I say space-time at the inner surface of the cylinder is “more curved” than the outside, I am (probably using the term too loosely but) referring to the idea that a region of space-time with a higher gravitational field is more curved than a region with a lower gravitational field (assuming the geometries of both regions are equal).
This isn't really the right way to describe curvature. What is proportional to the curvature tensor in GR is not "gravitational force" as it is usually thought of, but "tidal gravitational force".
Curvature is related to gravity, but it's a mistake to think of them as being synonyms.
The Equivalence Principle says that “all accelerated reference frames possesses a gravitational field” (http://en.wikipedia.org/wiki/Gravitational_time_dilation) . Obviously a test mass weighs more at the inside of the rotating cylinder than on the outside. I would also propose that a photon emitted from the surface of the cylinder would be red-shifted on the inside of the cylinder and blue-shifted on the outside. Therefore one could say that the gravitational field on the inside of the cylinder is greater than on the outside – thus “space-time is more curved on the inside”.
What you are calling the gravitational field is just the 4-accleleration of a particle that is following some particular curve. In this case, the curve is just a curve of constant coordinates.
This is also sometimes called the "connection", or the "Christoffel symbols".
This is, IMO anyay, what most people mean when they say "gravitational field". The term is rather vague, so some other people mean different things when they use exactly the same words.
Anyway, the sort of gravity you are talking about isn't directly realted to curvature in the sense of being a synonym.
BTW Thanks
pervect!

Your explanations were most helpful. The GEM equations are very interesting. It seems the one of interest in this case is the analog of Ampere’s law. It describes the curl of the gravitomagnetic field and how it changes sign (direction) from the inside to the outside of the cylinder and so explains why the gyroscopes would precess in opposite directions.
However if I might be so bold as to conjecture that that equation might be incomplete as there is no analog to the Equivalence Principle within electromagnetism. (As far as I know an accelerated reference frame cannot produce an electric field).
Just as the dE/dt term was a later addition to Ampere’s Law, perhaps in the GEM equation there should be a term accounting for the gravitational effects of an accelerated reference frame. In the case of my experiment, the EP effects would be asymmetric as one went from the inside to the outside of the rotating cylinder and “should” therefore produce an asymmetric precession of the gyroscopes. ??
This assumes that the gyroscopes in a non-accelerating reference frame can “feel” the effects of the accelerating reference frame of the cylinder. (But maybe this assumption is incorrect).
Redhat
An accelerated reference frame is just a change in viewpoint, a change in POV. Mathematically, the elemnt in GR which is closest to your idea of gravity are the Christoffel symbols. Because these symbols depend on the POV of the observer, though, they are not tensors. Tensors are reserved to those quantites that don't depened on the POV of any observer, they can be regarded philosphically as being independent of any observer. (They can also be regarded a bit like an object in an object-oriented programming language, in that they contain all the information needed to transform themselves to give their appearance according to any arbitrary observer).
Anyway, because they are not tensors, the Christoffel symbols aren't really a "field". There is basically no way that one is going to take things that are dependent on one's POV and make them not-dependent on one's POV. This is why the gravitational field isn't really a "field" in the usual sense, because to be a field in the usual sense, an object has to be representable by a tensor.