Why Does the Michelson-Morley Experiment Use T1-T2 Even After Rotation?

KIRIT PUROHIT
Messages
1
Reaction score
0
Pl. guide me for the doubts that i have in MME

In this experiment suppose L1 = L2 Then in this case will there be in any change in time difference T1-T2 calculated before and after rotation of the apparatus?

Another query is first we find T1-T2 now if first path is parallel to ether wind then T1>T2 & so T1-T2 is ok. But after rotating through 90 now T1 < T2 so why we do not write T2-T1?
 
Physics news on Phys.org
KIRIT PUROHIT said:
Pl. guide me for the doubts that i have in MME

In this experiment suppose L1 = L2 Then in this case will there be in any change in time difference T1-T2 calculated before and after rotation of the apparatus?
The hypothesis was that there should be a difference due to the speed of light being dependent upon the speed of the source relative to the medium (the ether). L1 and L2 were perpendicular to each other so as the Earth changed its position relative to the ether, there should be a difference between times taken for light to travel the two paths. As it turned out, there was a null result. No time difference was observed.

Another query is first we find T1-T2 now if first path is parallel to ether wind then T1>T2 & so T1-T2 is ok. But after rotating through 90 now T1 < T2 so why we do not write T2-T1?
But you would not know which direction the ether wind is travelling, so you would not know how either path is oriented to the ether wind. All you are interested in is measuring the magnitude of the time difference.

AM
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top