What is the negation of the statement

  • Thread starter Thread starter yxgao
  • Start date Start date
AI Thread Summary
The negation of the statement "For each s in R, there exists an r in R such that if f(r) > 0, then g(s) > 0" is "There exists an s in R such that for each r in R, f(r) > 0 and g(s) < 0." To find the negation of any logical statement, one can apply principles from Boolean logic, particularly focusing on contradictory statements. Key laws include the negation of universal and existential quantifiers, as well as the distribution of negation across logical operators. Understanding these principles allows for the effective transformation of statements into their negated forms. Mastery of these concepts is essential for logical reasoning and mathematical proofs.
yxgao
Messages
122
Reaction score
0
What is the negation of the statement "For each s in R, there exists an r in R such that if f(r) >0, then g(s) >0."

The answer is "There exists an s in R such that for each r in R, f(r) >0 and g(s) <0."

What is the general method to find the negation of any logical statement?

Thanks!
 
Physics news on Phys.org
Originally posted by yxgao
What is the general method to find the negation of any logical statement?
While I can't give you a general method, you may find it useful to review the concept of contradictory statements from Boolean logic:

All S is P is contradictory to Some S is not P

No S is P is contradictory to Some S is P

A statement and its contradictory cannot both be true (or both be false). Thus if "All S is P" is not true, then "Some S is not P" must be true. Of course, this only applies to statements that can be put in standard categorical form.
 
Basically, you just want to distribute the negation. Use the laws

\neg \forall x: P(x) = \exists x: \neg P(x)
\neg \exists x: P(x) = \forall x: \neg P(x)
\neg(x \wedge y) = \neg x \vee \neg y
\neg(x \vee y) = \neg x \wedge \neg y
\neg(x \Rightarrow y) = x \wedge \neg y
\neg(\neg x) = x
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top