Bilateral and non-bilateral components

  • Thread starter Thread starter surfer
  • Start date Start date
  • Tags Tags
    Components
AI Thread Summary
Bilateral components in electrical circuits allow current to flow in either direction, exemplified by resistors. In contrast, non-bilateral components have a preferred direction for current flow, such as diodes. The distinction is crucial for circuit design and analysis. Understanding these components aids in predicting circuit behavior. Accurate identification of bilateral and non-bilateral components is essential for effective electrical engineering.
surfer
Messages
6
Reaction score
0
What is the mean of bilateral and non-bilateral components in the electrical circuit?
 
Physics news on Phys.org
Well, I'd guess that in a bilateral component it doesn't matter which way the current passes through it (like a resistor), and a non-bilateral component has a preferred direction for the current to pass through it.

I'm sure someone will be along soon to confirm (or, more probably, correct) what I've said, since this isn't really my field of expertise!
 
Thank you for answer ,Cristo
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Unilateral and Bilateral Laplace Transform in Solving Differential Equations
Replies
1
Views
4K
How Does Raising Arms or Leg Amputation Affect the Center of Mass?
Replies
8
Views
10K
How many independent components does a tensor have?
Replies
18
Views
2K
Electric field on the axis of a ring-shaped charged conductor
Replies
1
Views
941
Discovering Auroralumina attenboroughii: A New PreCambrian Jellyfish Relative
Replies
1
Views
2K
Bilateral trade between all countries
Replies
2
Views
4K
Vector-Force image and resolve force
Replies
27
Views
2K
Confusion with force components
Replies
21
Views
2K
Calculate electric force using Coulomb's law (vector components are the struggle)
Replies
3
Views
1K
Understanding the Limitations of Superposition Principle in Electronics
Replies
2
Views
4K

Hot Threads

Recent Insights

Back
Top