Hurkyl #41 said:
The angle in a mixed spatial-temporal plane corresponds to relative velocity -- something that is presumably physically observable when two objects pass by each other. (Sorry, my brain was firmly in 'geometry' mode) Angle measure in such a plane is based on the hyperbola, and uses the hyperbolic trig functions. I think 'rapidity' is the term physicists use instead of 'angle'.
Ken G #42 said:
Relative velocity is not directly measurable, but redshift/blueshift is, so we can certainly pin our theory on a need to get the right answer for that. Certainly when there is gravity around, we need a more general concept than relative velocity, but I realize we are talking special relativity here. So is there really a physical concept of relative velocity even without any gravity? I'm not so sure that's a physical concept, it seems like yet another coordinate choice.
Yes, the "hyperbolic angle" between two timelike vectors is called "rapidity" and it is equal to \log_e k, where
k is the doppler factor (emitted frequency)/(observed frequency), which can be measured using only proper time. (The two timelike vectors are the 4-velocities of emitter and observer.) Note that if you rescale rapidity to be c \log_e k then it approximates to coordinate-speed at low speeds.
In terms of general relativity, it only makes unambiguous sense to measure rapidity "locally" i.e. for two observers passing by each other, so that gravitational doppler shift is excluded from consideration. In G.R. only
local measurements have physical significance; "remote" measurements get distorted by the curvature of spacetime and tend to be dependent on non-physical coordinates.
"Proper distance" between two objects
that are stationary relative to the observer requires no definition of simultaneity as you can take as long as you like to compare your objects against a ruler. It's only the measurement of moving objects that requires a clock synchronisation convention. The distance between two
events is the proper distance between two stationary objects each of which experiences one of the events.
So the interval
ds can be defined in terms of proper time (if timelike) or proper distance (if spacelike), neither requiring clock synchronisation.
Note that if you have a definition of "spatial distance" for stationary objects then you can define spatial angle via the Cosine Rule dc^2 = da^2 + db^2 - 2 \, da \, db \, \cos C.
Ken G #38 said:
DrGreg said:
On a final note, I believe the second postulate should really be interpreted as "the motion of a photon is independent of whatever emitted it", so that it is impossible for one photon to overtake another traveling in the same direction.
But that is a much weaker version, because different sources could still emit photons with the same properties but not isotropic speeds.
Yes, as I stated it, my 2nd postulate
is weaker than the common interpretation, because I demand no coordinate system. "Isotropic speed" implies a coordinate system to measure speed.
Ken G #38 said:
And if the postulate is "space plays no special role in the propagation, it's always the same", then note this only applies if we treat inertial observers as special. In short, the "special" in special relativity is somewhat oxymoronic.
"Special" means "ignoring gravity", rather than the status of inertial observers.
Inertial observers
are different to all other observers, in a physically measurable way: they do not experience proper acceleration, i.e. "G-forces", something they can determine using an appropriate accelerometer device, without a coordinate system. (And this definition works in GR as well as SR. Inertial observers still have special status in GR, but they no longer travel at constant velocity relative to each other.)
Forgive me if I'm explaining something you already know, Ken, but the mathematical description of spacetime makes a distinction between a 4D vector
X and its components (
t,
x,
y,
z). You can switch between lots of different coordinate representations, but they all represent the same vector which exists independently of its coordinates. Spacetime is equipped with an scalar "inner product"
g(
X,
Y) which is analogous to the "dot product" of 3D Euclidean vectors
x.y. The inner product, or "metric" is invariant, that is you always get the same answer for
g(
X,
Y) no matter what coordinate system you use to carry out the calculation. The properties of spacetime can described in terms of the properties of the metric (e.g.
g(
X,
Y+
Z) =
g(
X,
Y) +
g(
X,
Z) etc etc). And then
ds2 =
g(
dX,
dX).
So, mathematically, spacetime is defined as a four dimensional vector space equipped with a metric
g that satisfies certain conditions (which can all be expressed in a coordinate-free vector notation). I provide this as background information, as I know you are really looking for a physical rather than mathematical model.