Some quick problems before my exam 2morrow

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The discussion revolves around several chemistry problems related to quantum numbers, molecular bonding, and bond lengths. For the first question regarding the number of electrons allowed with n=5, the correct answer is 36, derived from the sum of orbitals corresponding to l values from 0 to n. The second question about the pi bond in CH2NF indicates that the bond is formed through sp^2-sp^2 orbital overlap. Lastly, when comparing carbon-carbon bond lengths, C2H2 is identified as having the shortest bond due to its triple bond structure. Overall, the focus is on understanding quantum mechanics in chemistry and molecular structure.
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Some quick questions before my Chem exam tomorrow. Here are some problems that were on a practice exam but I don't have the answers to them. I am stuck on all of these so i was wondering if you guys/gals can help me out with these. If you can't do all then one is fine.

how many electrons are allowed with n=5, l=?, m_l=-2, m_s=?
A. 3
B. 6
C. 10
D. 8
E. 25

The pi bond in CH2NF is formed with the following orbital overlap.
A. sp^2 - 2py
B. 2px - 2py
C. 2py - sp^3
D. sp^2 - sp^2
E. 2py - 2py

If the allowed values of the quantum number l were all integers from 0 to n, how many orbitals are allowed with n=5?
A. 64
B. 36
C. 83
D. 49
E. 25

In which of the following molecules is the C to C the shortest?
A. C2H6
B. C2H2
C. C2H4
D. H3CCOOH
E. H3CCN
 
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1,) 6 corresponding to l= 2,3,4 each with 2 spins

2.) possible sp^2-sp^2

3.) no of electrons

= \sum_0^{6} (2i+1) = 36

4.) triple bond will have shortest C-C distance hence C2H2
 
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