A dart player, standing 3.2m away from the darboard thorws a dart horizontally

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A dart player throws a dart horizontally from a distance of 3.2 meters at a speed of 12.4 m/s. The calculation involves determining the time it takes for the dart to reach the board and the vertical displacement due to gravity during that time. The vertical movement is influenced by the dart's initial vertical velocity, which is zero, leading to a downward displacement of 0.326 meters. The discussion emphasizes understanding the physics of projectile motion to solve the problem. The participant ultimately gains clarity on the solution process.
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a dart player, standing 3.2m away from the darboard... thorws a dart horizontally...

A dart player, standing 3.2m away from the dartboard, throws a dart horizontally at a speed of 12.4m/s. How far from the bull's eye(where the player aimed) did the dart stirke?

Answer: dy=0.326m (give a direction...


i don't get it, if you could show me how you got it, I've been trying and trying to solve it, but it doesn't work...

help is grealy appreciated , thanks.
 
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Well first consider the time it takes to hit the dart board..

then consider the vertical movement of the object (hint: what is the dart's initial vertical velocity?) and think gravity (constant acceleration...)... then how far it moved (vertically) in the time it takes to strike the dartboard...

can't say much more or I'd be giving the answer away...
 


oh, ok thanks i got it from here.
:]
 

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