- #1
mmmboh
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So I multiplied the heat equation by 2u, and put the substitution into the heat equation, and get 2uut-2uuxx=(u2)t=2(uux)x+2(ux)2.
I`m not sure where to go from there, I can integrate with respect to t, then I would have a u2 under the integral on the left side, but them I`m not sure where to go.
I also tried using the fact that the solution to the heat equation is
And I said that the integral was less than
[tex] \int_{-infinity}^{infinity} \ f(y)dy[/tex]
and then I squared both sides, and said that the integral squared was less than the square of the integral. Then I integrated both sides with respect to x, but the problem is now, I have a double integral on the right side :S.
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