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The discussion centers on the dynamics of sodium channels, specifically the interaction between the "hole" and the "blocker." The blocker begins to move at a lower voltage than when the hole opens, but it does so slowly, while the hole opens rapidly. When voltage increases quickly, the hole opens fully and allows sodium ions to enter the cell before the blocker can fully position itself. Conversely, if the voltage increases slowly, the blocker can fully occupy its position before the hole opens, resulting in a reduced ability to generate action potentials. This highlights the importance of the rate of voltage change in influencing sodium ion influx and neuronal excitability.
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please answer simple and descriptively
 
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There are two "parts" to the sodium channel. Let's call these the "hole" and the "blocker". The blocker starts to move at a lower voltage than the voltage at which the hole starts to open. However, the blocker moves slowly, while the hole opens quickly.

When the voltage is increased quickly, the blocker begins to move before the hole starts to open. As the hole opens much more quickly than the blocker moves, it is opens fully and let's sodium ions into the cell, even though the blocker started to move before the hole started to open. Finally, the blocker moves into place, and even though the hole is still open, sodium ions no longer get into the cell.

In contrast, if the voltage is increased slowly, the blocker will finish moving in place before the hole opens. So you will be less able to evoke spikes when the voltage is increased slowly.
 
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