Projectile Motion of Basketball Shot to Ring

AI Thread Summary
To solve the problem of a basketball shot from a height of 2.8m to a ring at 3.3m, the initial vertical velocity is calculated as 4.45 m/s and the horizontal velocity as 3.23 m/s. The challenge lies in determining the time of flight since this projectile does not start and end at the same height. The participant is unsure how to approach the time calculation, which is essential for finding the horizontal displacement. Understanding the relationship between vertical and horizontal motion is crucial for solving this type of projectile motion problem. Accurate calculations will lead to the horizontal distance traveled by the basketball before it reaches the ring.
Chooks
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Homework Statement



A basketball is thrown from a height of 2.8m above the ground and goes through a basketball ring that is 3.3m above the ground. If the release velocity was 5.5 m/s at an angle of 54 degrees upwards from the horizontal, calculate the horizontal displacement the ball will travel between being released and reaching the ring

Homework Equations



I know I have to find initial vertical and horizontal velocity and time

The Attempt at a Solution



I have found initial vertical velocity of 4.45m/s and horizontal velocity to be 3.23m/s

I don't know where to start with time as i have only ever done projectiles that take-off and land at the same height ?
 
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For any vertical or horizontal displacement, the time taken are equal.
 
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