How to calculate lattic energy of RbCl(s), in kJ/mol using Hess' Law

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To calculate the lattice energy of Rubidium chloride (RbCl) using Hess's Law, the following thermodynamic values are essential: the enthalpy of formation (ΔHformation) is -430.5 kJ/mol, the enthalpy of sublimation (ΔHsub) for Rubidium is 86 kJ/mol, the first ionization energy (ΔHion) of Rubidium is 402 kJ/mol, the bond dissociation energy (ΔHdiss) of Cl2(g) is 243 kJ/mol, and the electron affinity (ΔHea) of chlorine is +349 kJ/mol. By applying Hess's Law, the lattice energy can be derived by combining these values in a thermochemical cycle that accounts for the formation of RbCl from its gaseous ions. The discussion emphasizes the importance of these thermodynamic quantities in calculating lattice energy accurately.
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The enthalpy of formation (ΔHformation) of Rubidium chloride is -430.5 kJ/mol. The enthalpy of sublimation (ΔHsub) for Rubidium is 86 kJ/mol, and the first ionization energy (ΔHion) of Rubidium is 402 kJ/mol. The bond dissociation energy (ΔHdiss) of Cl2(g) is 243 kJ/mol, and the electron affinity (ΔHea) of chlorine is +349 kJ/mol.

So How do I calculate lattic energy of RbCl(s), in kJ/mol using Hess' Law
 
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