Conversion of translational momentum to angular momentum

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In the scenario described, mass m1 collides with a rigid bar attached to mass m2, creating a combined system. To determine the resulting translational and angular velocities, one must apply the principles of conservation of linear momentum and angular momentum. The final velocities of m1 and m2 can be denoted as v1 and v2, respectively. It is essential to select a pivot point for calculating the initial and final angular momenta. The discussion emphasizes the need to set up equations based on these conservation laws to solve for the final velocities.
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Suppose there was a mass, m1, traveling rightwards at v0. There is a second mass, m2, above the line of motion of m1, and which has a rigid, massless bar of length L attached to its center of mass. This bar extends downwards so that the terminal intersects with the path of m1. When m1 reaches this intersection, it attaches to the bar at its own center of mass, and m1 and m2 move as a single system. How can one find the resulting translational and angular velocities of the final system?
 
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Your title is misleading. Linear momentum and angular momentum are separately conserved. Let final velocities of m1 and m2 be v1 and v2. Write down equations embodying conservation of linear mometum and conservation of angular momentum. You will have to choose a point about which to calculate initial and final angular momenta.
 
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