What is the relationship between exponential and natural logarithm?

AI Thread Summary
The discussion focuses on the relationship between exponential functions and natural logarithms, specifically analyzing the function y(x) = log_x 4. Participants seek to identify the domain, range, and characteristics such as whether the function is increasing or decreasing, as well as finding the vertical asymptote and x-intercept. There is confusion regarding the clarity of the equation and the interpretation of logarithmic properties, particularly in relation to the equation y(x*) = 1. The conversation emphasizes understanding the surjectivity of logarithmic functions and the application of exponential functions to solve for x. Overall, the thread highlights the complexities of logarithmic functions and the need for clear communication in mathematical discussions.
Erin_Sharpe
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y = logx 4

identify the domain and range

state whether the function is increasing or decreasing, and identify the vertical asympotote, teh x-intercept and the value of x at y = 1

I need some help!

thank you in advance!
 
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The 4 in your expression appears to be hanging out in space. It would be helpful if you could write the equation more clearly.
 
So your function is:
y(x)=\log_{x} 4

Can you determine the domain and range...??

Discuss the sign of its derivative...


Daniel.

P.S.Can u solve the equation y(x*)=1??Find x*...
 
I believe that loga(x) is only defined for a> 0. Does that help.
 
Also I don't think that loga(x) is defined for a=1.
 
Write
y(x)=\frac{\ln 4}{\ln x}

Cau u see now what is the range??What about the domain?

Daniel.
 
See I thought x was 2??
 
What "2"??Where did u pick it out?You mean the solution to the equation
\frac{\ln 4}{\ln x} =1

I hope you're only kidding...

Daniel.
 
no, I'm kidding. this problem might as well be in chinese for all i understand of it
 
  • #10
*** NOT kidding
 
  • #11
Write it like that
\ln 4=\ln x

Use the fact that logaritm is a surjective function...

Daniel.
 
  • #12
i'm sorry I'm not trying to be difficult i just completely don't understand what you are talking about.
 
  • #13
Erin_Sharpe said:
i'm sorry I'm not trying to be difficult i just completely don't understand what you are talking about.

Okay.Do you know the relation between the exponential and the natural logarithm?If so,apply exponential on both sides of the last equation and tell me what u get.

Daniel.
 
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