Baluncore said:
Generated voltage is proportional to the rate the magnetic field crosses the windings.
The open circuit voltage produced by a permanent magnet DC generator is proportional to the RPM of the generator. When you load the generator at a fixed RPM, it's voltage is reduced by the output current flowing through the resistance of the generator windings.
A permanent magnet alternator will produce an AC voltage that has amplitude proportional to RPM. (The frequency will also be proportional to RPM). As the RPM rises, the voltage will rise, so the load will draw more current. Unless there is some form of regulation or control the power dissipated in the load will rise in proportion to the square of the RPM.
If there is no field current control, the RPM of an alternator should be regulated to produce the supply voltage needed by the load. In a motor vehicle the RPM varies, field control is needed to regulate the voltage that charges the battery.
This is not quite correct. Even if rpm were held constant, i.e. cruise control engaged, as the load current varies, the filed current must vary to keep terminal voltage constant.
If the alternator open circuit voltage is measured (no load), then loaded, the voltage drop incurred is due to more than just the winding resistance of the stator, but stator winding
inductance. The inductive reactance is generally much larger than the resistance.
For an alternator the inductive reactance is typically 100% plus or minus 50%. The resistance is maybe 2% to 5%. When a load is placed across the terminals, the voltage drops from its open circuit value to Voc - (R + jX), where X = Lω.
If load is held constant while speed increases, then power goes up with speed squared only until X equals/exceeds R. At that point power levels off. Although the open circuit voltage increases, the fraction of open circuit voltage, Voc, that is impressed on the load decreases. This is due to X increasing so that a smaller fraction of open circuit voltage appears at the load. Also, current asymptotically approaches constant value since increase in Voc and increase in L are equal.
Think about conservation of energy. If power equals Tω, T=torque, then raising ω results in higher power, varying as ω to 1st power if torque is constant. If power at electrical load increased with the square of ω, CEL (cons of energy law) is violated. In order for electric power to increase w/ square of ω, T must increase as well.
Just some clarification. Thanks.
Claude