How Do You Calculate Force on a Car Impacting a Tree at 60km/h?

AI Thread Summary
To calculate the force on a car impacting a tree at 60 km/h, one can use the formula v_final^2 - v_initial^2 = 2as, where 's' is the stopping distance and 'a' is the deceleration. Assuming a constant deceleration during impact, the acceleration can be determined from the change in velocity and the distance the car crumples upon impact. Once the acceleration is known, the force can be calculated using Newton's second law, F = ma, where 'm' is the mass of the car. It's important to note that a heavier car will require more force to stop. This approach provides a foundational understanding of kinematics and momentum in collision scenarios.
Physics_Student101
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Hello everyone,

Im new to this forum so I am not entirely sure how it works,
I have a physics assignment in which i must analyse kinematics, impulse and momentum, friction, energy and circular motion, I am currently working on a car design and i was wondering if anyone could tell me the formulae i need to analyse the force on an impact on a car traveling at a certain speed let's say 60km/h colliding with a tree.
 
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Physics_Student101 said:
Hello everyone,

Im new to this forum so I am not entirely sure how it works,
I have a physics assignment in which i must analyse kinematics, impulse and momentum, friction, energy and circular motion, I am currently working on a car design and i was wondering if anyone could tell me the formulae i need to analyse the force on an impact on a car traveling at a certain speed let's say 60km/h colliding with a tree.

You can estimate the force by assuming a constant deceleration and constant force during the time of impact. Under this assumption, you can find the acceleration from the change in velocity and the distance the car moves while it is stopping, which would be the amount by which the car crumples on impact (a half meter or so perhaps). The equation that relates these quantities is

v_{final}^2 - v_{initial}^2 = 2as

where s is the stopping distance and a is the acceleration (negative for stopping). Once you have the acceleration, the force acting on the car is found from Newton's second law

F = ma

Obviously it takes more force to stop a more massive car.
 
Year 11 - So it's coursework, that brief is fairly large, when I visited a school recently their question was quite fixed and not open ended, perhaps you could tell us your brief more succintly?

-NewScientist
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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