Finding general solution for object falling in air

andrey21
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1. Using separation of variables show that:
v' = (cd/M)(v^2) - g has a general solution of:

v = 20SQRT10 x ((1+Ae^(t/SQRT10)/(1-Ae^(t/SQRT10))



Homework Equations





The Attempt at a Solution


Have attempted numerous times with little success help appreciated!
 
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Divide both sides by


\frac{cd}{M}v^2 - g
 
Just come to the correct answer and now is asking to find the terminal velocity. How would I go about doing that?
 
Jamiey1988 said:
Just come to the correct answer and now is asking to find the terminal velocity. How would I go about doing that?

That would be where the rate of change or velocity is zero.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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