Why Does RMS Velocity Increase During Adiabatic Compression?

AI Thread Summary
The discussion focuses on the relationship between adiabatic compression and the increase in root mean square (rms) velocity of a gas. Adiabatic compression occurs without heat transfer, leading to a rise in temperature, which in turn affects the gas's kinetic energy. The equations provided illustrate how temperature and volume changes during compression relate to rms velocity. As the gas is compressed, its volume decreases, resulting in an increase in temperature and consequently, an increase in rms velocity. Understanding these principles is crucial for grasping the thermodynamic behavior of gases under adiabatic conditions.
UCstudent
Messages
7
Reaction score
0
rms velocity and compression. Please help!

Homework Statement



Explain why the rms velocity of a gas increases when it is adiabatically compressed.

Homework Equations



None

The Attempt at a Solution



I know that compressing a gas decreases the volume, but I don't know details on how it would effect rms velocity
 
Physics news on Phys.org


Do you understand what adiabatically compressed means? If you don't, google it :-)
 


If you compress a gas adiabatically, no heat is transferred from the gas to its surroundings. You know that compressing a gas increases the temperature (and you can calculate by how much using your adiabatic relations).

T*V^{γ-1} = constant
T_{0}*V_0^{γ-1} = T_1*(V_0 + ΔV)^{γ-1}
Thus
T_1 = T_{0}*(V_0/(V_0 + ΔV))^{γ-1}
And
ΔT = T_1 - T_0

Then
ΔE = (3/2)N k_b ΔT= (1/2)N m (Δv)^2
Or
Δv = \sqrt{(3/2) (k_b ΔT)/m}
 
Last edited:


And I was going to make you figure it out yourself. :-(:wink:
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top