International reference triple point

AI Thread Summary
The triple point of water, defined at 273.16K and 611Pa, serves as a crucial reference for temperature measurement. To create a reliable thermometer, one must ensure it is linear in temperature and calibrate it using the triple point and an approximate 0K measurement. Other triple points can also be measured for additional reference points in temperature scales. The discussion emphasizes the importance of these fixed points in establishing the Kelvin scale. Resources for constructing thermometers can be found through search engines.
Outrageous
Messages
373
Reaction score
0
I know the triple point of water is at 273.16K and atmospheric pressure
But how are we going to make it as a reference when we measure temperature of something?

Thank you
 
Physics news on Phys.org
Simplified: Get a thermometer which is linear in temperature, check its measurement at (approximately) 0K and at the triple point, adjust the scale to get the correct values there.

It helps to measure other triple points, so they can be used as additional reference.

I know the triple point of water is at 273.16K and atmospheric pressure
611Pa, or 0.006 times the atmospheric pressure.
 
mfb said:
Simplified: Get a thermometer which is linear in temperature, check its measurement at (approximately) 0K and at the triple point, adjust the scale to get the correct values there.

It helps to measure other triple points, so they can be used as additional reference.

611Pa, or 0.006 times the atmospheric pressure.

So do you mean that between 0K and triple point is used to do temperature scale?
approximately to 0K mean we cool it as low as possible?
Do you have any link or reading source that explain to make thermometer?
Thank you
 
0K and the triple point of water are the fixed reference points for the temperature scale. They are used to fix the kelvin scale.

Do you have any link or reading source that explain to make thermometer?
Search engines should find some.
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
Back
Top