What is the mass of the ice cube?

  • Thread starter Thread starter tobyguy
  • Start date Start date
  • Tags Tags
    Cube Ice Mass
AI Thread Summary
To determine the mass of the ice cube placed in 500 grams of water, the energy lost by the water as it cools from 60 to 18 degrees Celsius must equal the energy gained by the ice cube. The heat lost by the water is calculated as 500 grams multiplied by the specific heat capacity of water (1 cal/g°C) and the temperature change of 48 degrees. The heat gained by the ice cube includes the heat of fusion (80 cal/g) for melting and the energy required to raise the temperature of the resulting water to 18 degrees. The equation Q_lost = Q_gained must account for both the heat consumed to melt the ice and the heat used to increase the temperature of the melted ice. This calculation ultimately reveals the mass of the ice cube.
tobyguy
Messages
11
Reaction score
0
take an ice cube at 0 degrees C and place it in 500 grams of water at 60 degrees C . The final temperature is 18 degrees C . What is the mass of the ice cube? heat of fusion for water is 80 cal per g. Anyone?
 
Physics news on Phys.org
Q_{gained} = -Q_{lost}
You know that 500 grams of water decreases in temperature from 60 to 18 degrees celsius and that C_{water} in terms of calories is 1, so the energy lost by the 60 degrees water would be: 500\times 1 \times -48. Figure out Q_{gained}. Don't forget to add the heat of fusion for x grams of the ice-cube to your heat gained.
 
You mean subtract...From |Q_{lost}|=|Q_{gained}| he should subtract the heat consumed/used to melt and the rest is used to increase temperature of water to 18°.

Daniel.
 
Yeah by add I meant "factor in". Sorry if I was unclear.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top