Preference of Angular frequency over frequency for sinusoidal graphs

AI Thread Summary
The discussion centers on the preference for angular frequency (ω) over frequency (ν) when analyzing sinusoidal graphs. The primary reason for this preference is that using ω simplifies calculations by eliminating the need for repeated factors of 2π, as trigonometric functions are more straightforward in radians. The relationship between displacement, velocity, and acceleration becomes clearer without the 2π factor when using ω. Examples provided illustrate that equations for oscillation frequency, such as for a mass on a spring or a simple pendulum, utilize ω without introducing 2π. This approach enhances clarity and efficiency in mathematical expressions related to oscillatory motion.
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Quote from 'The Physics of Vibrations and Waves by H.J.Pain': "However when we solve the equation of motion we shall find that the behaviour of x with time has a sinusoidal or cosinusoidal dependence, and it will prove more appropriate to consider not \nu, but the angular frequency \omega = 2\pi\nu so that the..."
My question is, why are we prefering \omega over \nu just because of the fact that the graph will be sinusoidal/cosinusoidal? Does it make the calculations somehow easy, or has it got some other purpose?
 
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The math works out MUCH easier if the trig functions are measured in radians. Otherwise, there are far too many factors of ##2\pi## to keep track of.
 
so, according to you, we prefer \nu over \omega. O.o but the book says that we prefer \omega over \nu. \omega contains 2\pi
 
The way I interpret your notation, ##\nu## means the number of complete cycles of the oscillation per unit time, and ##\omega## means the number of radians per unit time.

The book has used ##2\pi## once in its definition or explanation of what ##\omega## is. You won't find ##2\pi## again when you use ##\omega##.

For example if the displacement of something is ##A \cos \omega t##, its velocity is ##-A\omega \sin \omega t## and its acceleration is ##-A\omega^2 \cos \omega t##. No factors of ##2\pi##.

If you have a mass m on a spring of stiffness, the oscillation frequency is ##\omega = \sqrt{k/m}##. For a simple pendulum, ##\omega = \sqrt{g/l}##. Again, no factors of ##2\pi##.
 
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ah, i see... Thanks a lot for the help, sir ^_^
 
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