What Formula to Use for Elevator's Constant Acceleration Problem?

AI Thread Summary
To solve the elevator's constant acceleration problem, use kinematic equations to determine the distance and time for each phase of the elevator's motion. For part (a), calculate the distance the elevator travels while accelerating to its maximum speed using the formula x = 1/2at². For part (b), break the journey into three phases: acceleration to top speed, constant speed travel, and deceleration back to rest. Calculate the time and distance for each phase, ensuring consistent units throughout the calculations. This structured approach will yield the correct answers for the total distance and time of the elevator's run.
mb85
Messages
44
Reaction score
0
hello. i am confused on what forumla in particular you use to figure the answer out?

A certain elevator cab has a total run of 209 m and a maximum speed is 322 m/min, and it accelerates from rest and then back to rest at 1.16 m/s2. (a) How far does the cab move while accelerating to full speed from rest? (b) How long does it take to make the nonstop 209 m run, starting and ending at rest?
 
Physics news on Phys.org
Assuming the acceleration is constant, you can use a=∆v/∆t, and then x=1/2at2. For the second part, you'll need to separate into three phases: acceleration, constant velocity, and decceleration. Find the time each part takes. Also, remember to use the consistent units.
 
im still confused.. and am not getting the correct answer on egrade. :(
 
there's three separate parts:
1. the car is accelerating to its top speed
2. the car is moving at its top speed
3. the car is decelerating to rest

for part A, you just need to use kinematics. you are given enough information to use the equations and get the answer.

for part B, you need to use the three parts. find the distance that the car travels at the max velocity, and get the time. you can add this time to the time it takes to accelerate and decelerate.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top