Calculating Speed to Catch a Ball Thrown from a Building

AI Thread Summary
To determine the average speed required for a person to catch a ball thrown from a 25.6 m tall building, one must first calculate the time it takes for the ball to reach the ground. The ball is thrown upward with an initial speed of 12 m/s, and its motion can be analyzed using kinematic equations that relate position, velocity, and acceleration. Once the time for the ball's descent is established, the average speed of the runner can be calculated based on the distance of 29.4 m from the building. The runner must cover this distance in the same time it takes for the ball to fall to the ground. Understanding these physics principles is essential for solving the problem effectively.
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im practically lost in physics and need some help. it would be greatly appreciated.

A ball is thrown upward from the top of a 25.6 m tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 29.4 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?

i am really lost in physics , and need some help. it would be greatly appreciated. thankyou

A ball is thrown upward from the top of a 25.6 m tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 29.4 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?
 
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What are the equations that relate position, velocity and acceleration of an object? Use those equations to figure out how the ball moves with time as it goes up, stops at the top of its arc, and then accelerates down. These equations will let you figure out what time the ball will reach the bottom of the building. Then given the distance of the runner initially, you can figure out the speed needed to get the runner there at the same time. Too bad they didn't tell you how tall the runner is -- I guess you have to assume that they make a shoestring catch (catch the ball just as it reaches the ground).
 
The elapsed time for the ball to reach the ground will be the same time for the catcher to cover the 29.4 meters (and then splat against the wall!).
 
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