Pittsburgh to Phoenix Flight Time: 3h 36m - Airspeed & Wind Speed Calculation

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An airplane flying from Pittsburgh to Phoenix takes three hours and 36 minutes against a headwind, covering a distance of 1800 miles. The return flight takes three hours with a tailwind. To find the airspeed of the plane and the wind speed, it is necessary to set up simultaneous equations based on the two different flight times. The equations represent the plane's speed minus the wind speed for the outbound flight and the plane's speed plus the wind speed for the return flight. Solving these equations will yield the constant speeds of both the airplane and the wind.
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An airplane flying into a headwind travels the 1800 mile flying distance between Pittsburgh, Pennsylvania, and Phoenix, Arizona, in three hours and 36 minutes. On the return flight, the distance is traveled in 3 hours. Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.

I tried using vectors but...I'm just lost on this question.
 
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Well, if this question is supposed to be as straightforward as it sounds, then I assume they mean the speed of the plane stays constant relative to the wind speed.

Then, on the first flight, the plane travels at a speed of vp - va, and on the return flight it travels at a speed of vp + va, where vp is plane speed and va is air speed.

You should be able to set up simultaneous equations and solve for the two unknowns.
 
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