How Deep Is the Lake After Dropping a Ball from 30 Meters?

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A heavy ball dropped from a height of 30 meters hits the water with a velocity of 24.3 m/s. After impacting the water, it continues to sink at this constant speed for 10 seconds. The calculation shows that the lake's depth is 243 meters, derived from multiplying the sinking velocity by the time taken to reach the bottom. The physics involved includes using the equations of motion to determine the final velocity and the distance traveled. Therefore, the lake is determined to be 243 meters deep.
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A heavy ball is dropped into a lake from a height of 30.0m above the water. it hits the water with a certain velocity and continues to sink to the bottom of the lake at this same constant velocity. It reaches the bottom of the lake 10.0s after it was dropped. How deep is the lake.


And the solution i got:


vf^2=vi^2+2ad
vf^2=2(-9.81)(30.0)
vf=24.3m/s


d=vt
=(24.3)(10)
=24.3m deep
 
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24.3*10=243m
 

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